java 生成有序账号的实现方法
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2024-03-11 23:24:55
如下所示：
for (int i= 0; i<= 1084; i++) {
if (string.valueof(i+1).length() == 1...
如下所示：
for (int i= 0; i<= 1084; i++) {
if (string.valueof(i+1).length() == 1) {
username = "sys_000" + (i+1);
}
if (string.valueof(i+1).length() == 2) {
username = "sys_00" + (i+1);
}
if (string.valueof(i+1).length() == 3) {
username = "sys_0" + (i+1);
}
if (string.valueof(i+1).length() == 4) {
username = "sys_" + (i+1);
}
system.out.println(username);
}
sys_0001 sys_0002 sys_0003 sys_0004 sys_0005 sys_0006 sys_0007 sys_0008 sys_0009 sys_0010 sys_0011 sys_0012 sys_0013 sys_0014 sys_0015 sys_0016 sys_0017 sys_0018 sys_0019 sys_0020 sys_0021 sys_0022 sys_0023 sys_0024 sys_0025 sys_0026 sys_0027 sys_0028 sys_0029 sys_0030 sys_0031 sys_0032 sys_0033 sys_0034 sys_0035 sys_0036
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