ACM-ICPC 2018 焦作赛区网络预赛 L. Poor God Water(水)
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2022-03-12 15:39:34
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题目链接:https://nanti.jisuanke.com/t/31718
样例输入
1 1 2
1 1 4
1 1 1
样例输出
Yes
Yes
No
题意:a*b*c的立方体,问能不能用1*1*2的立方体不重叠的放满
思路:胆子放大,猜完就交,abc三遍任意一边能被2整除,就可以做到不重叠放满
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<iostream>
#include<vector>
#include<queue>
#define maxn 300005
using namespace std;
int main(){
int a,b,c;
while(~scanf("%d%d%d",&a,&b,&c)){
if(c%2==0)printf("Yes\n");
else if(a%2==0)printf("Yes\n");
else if(b%2==0)printf("Yes\n");
else printf("No\n");
}
return 0;
}