C# 拼图魔方小游戏

工作闲暇之余去逛了逛codeproject，刚好现有项目主要用到就是winform，浏览了下照片，找到上周带着蛋挞打疫苗回家的照片，于是新生一记，如何把这些图片玩起来~

80后应该都有印象，小时候有种玩具，叫做拼图魔方，90后00后的世界这种玩具应该早已灭绝了。一个塑料小板，上面分隔了很多小图框，通过移动这些小图框，最后拼接成完整的图片

话不多说开始吧~ 先上一张原图

代码也很简单，主要就是通过bitmap分隔现有（后面有时间可以优化下，让玩家自动上传图片，应该会更有意思）图片，然后random随机打乱分割后图片的顺序，通过点击小方格来完成图片的拼图，为了更方便玩家，每个小方格添加了序号，玩家也可以不参考原图，按照小方格上的序号进行拼图

序号功能实现主要是类mybutton集成父类button实现：

public class mybutton : button
  {
    private int number; 
    public int number
    {
      get
      {
        return this.number;
      }
      set
      {
        this.text = value.tostring();
        this.number = value;
      }
    } 
    public mybutton()
    {
    }
  }

随机分隔

random r = new random();
      int[] a = new int[24];
      int i = 0;
      int b;
      bool exist;
      while (i != a.length)
      {
        exist = false;
        b = (r.next(24) + 1);
        for (int j = 0; j < a.length; j++)
          if (a[j] == b) exist = true;
        if (!exist) a[i++] = b;
      }
      for (int j = 0; j < a.length; j++)
        buttonarray[j].number = a[j];
      // set picture pieces as the background image
      int number;
      int row, column;
      for (int k = 0; k < 5; k++)
      {
        for (int j = 0; j < 5; j++)
        {
          if (k == 4)
            if (j == 4) break;
          number = buttonarray[k * 5 + j].number; //get the number of button
          row = (number - 1) / 5;
          column = (number - 1) - (row * 5);
          buttonarray[k * 5 + j].image = currentbitmapimage.clone(new rectangle(new point(column * 75, row * 75), new size(75, 75)), system.drawing.imaging.pixelformat.dontcare);
        }
      }

点击小方格，通过改变当前点击的小方格x,y坐标来更新小方格的位置

private void mybutton_locationchanged(object sender, eventargs e)
    {
      mybutton a = sender as mybutton;
      youwin = true;
      int buttonnumber;
      this.numberofmoves++;
      if (buttonarray == null)
      {
        this.frmmain_load(sender, e);
      }
      for (int i = 0; i < 5; i++)
      {
        if (youwin == false)
          break;
        else for (int j = 0; j < 5; j++)
          {
            buttonnumber = i * 5 + j;
            if (i == 4 && j == 4)
              break;
            else if (getnumber(buttonarray[buttonnumber].location.x, buttonarray[buttonnumber].location.y) == buttonarray[buttonnumber].number)
              continue;
            else
            {
              youwin = false;
              break;
            }
          }
      }
      if (youwin)
      {

        if (messagebox.show("you win this game in " + this.numberofmoves.tostring() + " moves\n\rdo you want to play another game ?", "congratulation", messageboxbuttons.yesno) == dialogresult.yes)
          this.loadnewgame();
        else
          this.close();
      }
    }

private void mybutton_locationchanged(object sender, eventargs e)
    {
      mybutton a = sender as mybutton;
      youwin = true;
      int buttonnumber;
      this.numberofmoves++;
      if (buttonarray == null)
      {
        this.frmmain_load(sender, e);
      }
      for (int i = 0; i < 5; i++)
      {
        if (youwin == false)
          break;
        else for (int j = 0; j < 5; j++)
          {
            buttonnumber = i * 5 + j;
            if (i == 4 && j == 4)
              break;
            else if (getnumber(buttonarray[buttonnumber].location.x, buttonarray[buttonnumber].location.y) == buttonarray[buttonnumber].number)
              continue;
            else
            {
              youwin = false;
              break;
            }
          }
      }
      if (youwin)
      {

        if (messagebox.show("you win this game in " + this.numberofmoves.tostring() + " moves\n\rdo you want to play another game ?", "congratulation", messageboxbuttons.yesno) == dialogresult.yes)
          this.loadnewgame();
        else
          this.close();
      }
    }

具体效果如下：

代码有很多已知的可以优化的地方，后面有闲暇时间会处理，如果大家有更好的建议，不妨在下方评论区告知，在此感谢~

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