Mysql inner join on的用法实例(必看)
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2022-06-14 15:14:22
语法规则
select column_name(s)
from table_name1
inner join table_name2
on table_...
语法规则
select column_name(s) from table_name1 inner join table_name2 on table_name1.column_name=table_name2.column_name
先创建两个表,1.用户,2.用户类别
用户表
create table `user` ( `id` int(32) not null auto_increment, `name` varchar(16) not null, `kindid` int(32) not null, primary key (`id`) ) engine=myisam default charset=utf8;
用户类别表
create table `userkind` ( `id` int(32) not null auto_increment, `kindname` varchar(16) not null, primary key (`id`) ) engine=myisam default charset=utf8;
插入一些数据到user表
insert into `user` values (1,'小明',1),(2,'小红',1),(3,'涵涵',2);插入一些数据到 userkind表
insert into `userkind` values (1,'普通会员'),(2,'vip会员');
如图:
下面是控制台的查询例子:
enter password: **** welcome to the mysql monitor. commands end with ; or \g. your mysql connection id is 2 server version: 5.5.40 mysql community server (gpl) copyright (c) 2000, 2014, oracle and/or its affiliates. all rights reserved. oracle is a registered trademark of oracle corporation and/or its affiliates. other names may be trademarks of their respective owners. type 'help;' or '\h' for help. type '\c' to clear the current input statement. mysql> use join; database changed mysql> select * from `user`; +----+------+--------+ | id | name | kindid | +----+------+--------+ | 1 | 小明 | 1 | | 2 | 小红 | 1 | | 3 | 涵涵 | 2 | +----+------+--------+ 3 rows in set (0.00 sec) mysql> select * from `userkind`; +----+----------+ | id | kindname | +----+----------+ | 1 | 普通会员 | | 2 | vip会员 | +----+----------+ 2 rows in set (0.00 sec) mysql> select * from `user` inner join `userkind` on user.kindid=userkind.id; +----+------+--------+----+----------+ | id | name | kindid | id | kindname | +----+------+--------+----+----------+ | 1 | 小明 | 1 | 1 | 普通会员 | | 2 | 小红 | 1 | 1 | 普通会员 | | 3 | 涵涵 | 2 | 2 | vip会员 | +----+------+--------+----+----------+ 3 rows in set (0.02 sec) mysql> select `id` as `用户id`,`name` as `用户名`,`kindname` as `用户类别` from `user` inner join `userkind` where user.kindid=userkind.id; error 1052 (23000): column 'id' in field list is ambiguous mysql> select `user`.`id` as `用户id`,`name` as `用户名`,`kindname` as `用户类别 ` from -> `user` inner join `userkind` where `user`.`kindid`=`userkind`.`id`; +--------+--------+----------+ | 用户id | 用户名 | 用户类别 | +--------+--------+----------+ | 1 | 小明 | 普通会员 | | 2 | 小红 | 普通会员 | | 3 | 涵涵 | vip会员 | +--------+--------+----------+ 3 rows in set (0.00 sec) mysql> select `user`.`id` as `用户id`,`name` as `用户名`,`kindname` as `用户类别 ` from `user` inner join `userkind` on `user`.`kindid`=`userkind`.`id`; +--------+--------+----------+ | 用户id | 用户名 | 用户类别 | +--------+--------+----------+ | 1 | 小明 | 普通会员 | | 2 | 小红 | 普通会员 | | 3 | 涵涵 | vip会员 | +--------+--------+----------+ 3 rows in set (0.00 sec) mysql>
需要注意的是: 这里的on 基本等价于where(本人感觉)
当 column (字段) 两个表都有 却分不清时,需要用`表名`.`字段名` 进行分辨。
as就是取别名了。看上面例子就知道!
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