mysql中的一些稍微复杂用法实例代码
前言
mysql的语法相信对大家来说都不是难事,但是本文主要给分享了一些mysql复杂用法的相关内容,通过这篇文章相信大家会对mysql更深的了解一些,下面话不多说了,来一起看看详细的介绍吧
一对多数据显示成一行
group_concat(expr)
1、涉及的表关系:teacher表、teacher_subject_rel表(教师所能教的学科表)、subject表
2、业务场景: 需要拉取所有教师的编号(teacher_no)、学科名(subject_name)。   教师表(teacher)和学科(teacher_subject_rel)是一对多关系, 往往查询出现的是同一教师多条 数据。我们希望得到每个教师一条数据 学科拼接成一条
1、基本语法
group_concat( [distinct] 要连接的字段 [order by 排序字段 asc/desc] [separator '分隔符'] )
2、例子
select t.teacher_id as '教师id', t.teacher_no '教师编号', ( select group_concat(s.subject_name) from teacher_subject_rel tsr left join `subject` s on tsr.subject_id = s.subject_id where t.teacher_id = tsr.teacher_id ) as '学科' from teacher t
子查询、查询临时表、exists
例子
select * from ( select o.id, o.student_intention_id, s. name, s.area_id, a.area_name, s.exam_year, o. status, case o. status when '1' then '待提交' when '2' then '待指派' when '3' then '已完成' when '4' then '处理中' end statusname, case o.emergency_degree when '1' then '正常' when '2' then '紧急' when '3' then '非常紧急' end emergencydegreename, o.emergency_degree, o.update_time, ( select first_lesson_time from jx_strategy where jx_lesson_plan_order_id = o.id and status in (2, 7) and first_lesson_time > now() order by first_lesson_time asc limit 1 ) as first_time, ( select deal_user_id from jx_strategy where jx_lesson_plan_order_id = o.id and status <> 7 and deal_user_id <> 0 order by id desc limit 1 ) as deal_user_id from jx_lesson_plan_order o left join student s on s.student_intention_id = o.student_intention_id left join area a on s.area_id = a.id where o. status <> 1 and s.phone = '18501665888' and o.emergency_degree = 1 and o. status = 2 and s.exam_year = '2015' and o.update_time >= '2018-08-14 20:28:55' and o.update_time <= '2018-08-14 20:28:55' ) as a where 1 = 1 and a.deal_user_id = 145316 and a.first_time >= '2018-08-17 00:00:00' and a.first_time <= '2018-08-30 00:00:00' and exists ( select * from jx_strategy js where js.jx_lesson_plan_order_id = a.id and js. status in (2, 7) and js.subject_id in (2, 3) ) order by a.update_time desc limit 0, 10
update 关联变量条件修改
1、涉及的表关系: user_info表中的 id_number(身份证号) teacher表中的birth字段、 关联关系usrer_id = teacher_id
2、业务场景:获取用户身份证上的出生日期将出生日期更新在birth字段
update teacher t inner join ( select t.teacher_id, t.birth, u.id_number, concat(substring(u.id_number, 7, 4), '-', substring(u.id_number, 11, 2), '-', substring(u.id_number, 13, 2)) as birth1, u.reg_date, t.exit_time from teacher t inner join user_info u on u.user_id = t.teacher_id ) info on info.teacher_id = t.teacher_id set t.birth = info.birth1 where info.reg_date > '2018-08-20 00:00:00' and info.id_number is not null and (info.birth is null or t.birth = '') and t.is_train = 1
总结
以上就是这篇文章的全部内容了,希望本文的内容对大家的学习或者工作具有一定的参考学习价值,如果有疑问大家可以留言交流,谢谢大家对的支持。
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