Python实现的批量下载RFC文档

程序员文章站 2022-05-14 13:56:07

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RFC文档有很多，有时候在没有联网的情况下也想翻阅，只能下载一份留存本地了。
看了看地址列表，大概是这个范围：
http://www.networksorcery.com/enp/rfc/rfc1000.txt
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http://www.networksorcery.com/enp/rfc/rfc6409.txt

哈哈，很适合批量下载，第一个想到的就是迅雷……
可用的时候发现它只支持三位数的扩展(用的是迅雷7)，我想要下的刚好是四位数……
郁闷之下萌生自己做一个的想法！
这东西很适合用python做，原理很简单，代码也很少，先读为快。
代码如下：

复制代码代码如下:

#! /usr/bin/python
'''
File : getRFC.py
Author : Mike
E-Mail : Mike_Zhang@live.com
'''
import urllib,os,shutil,time

def downloadHtmlPage(url,tmpf = ''):
i = url.rfind('/')
fileName = url[i+1:]
if tmpf : fileName = tmpf
print url,"->",fileName
urllib.urlretrieve(url,fileName)
print 'Downloaded ',fileName
time.sleep(0.2)
return fileName

# http://www.networksorcery.com/enp/rfc/rfc1000.txt
# http://www.networksorcery.com/enp/rfc/rfc6409.txt
if __name__ == '__main__':
addr = 'http://www.networksorcery.com/enp/rfc'
dirPath = "RFC"
#startIndex = 1000
startIndex = int(raw_input('start : '))
#endIndex = 6409
endIndex = int(raw_input('end : '))
if startIndex > endIndex :
print 'Input error!'
if False == os.path.exists(dirPath):
os.makedirs(dirPath)
fileDownloadList = []
logFile = open("log.txt","w")
for i in range(startIndex,endIndex+1):
try:
t_url = '%s/rfc%d.txt' % (addr,i)
fileName = downloadHtmlPage(t_url)
oldName = './'+fileName
newName = './'+dirPath+'/'+fileName
if True == os.path.exists(oldName):
shutil.move(oldName,newName)
print 'Moved ',oldName,' to ',newName
except:
msgLog = 'get %s failed!' % (i)
print msgLog
logFile.write(msgLog+'\n')
continue
logFile.close()