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Lua编程示例(六): C语言调用Lua函数

程序员文章站 2022-03-07 10:36:42
c++端: #include "stdafx.h" lua_state *l; void load_lua(lua_state **l,char *fil...

c++端:

#include "stdafx.h"

lua_state *l;
void load_lua(lua_state **l,char *filename){
 *l=lual_newstate();
 lual_openlibs(*l);
 if(lual_loadfile(*l,filename) || lua_pcall(*l,0,0,0)){
 lual_error(*l,"load file error! %s",lua_tostring(*l,-1));
 }
}
int _tmain(int argc, _tchar* argv[])
{
 load_lua(&l,"raw.lua"); //此处若直接传入l会出错
 lua_getglobal(l,"gettable");
 if(lua_pcall(l,0,1,0) !=0){
 lual_error(l,"pcall wrong %s",lua_tostring(l,-1));
 }
 lual_checktype(l,1,lua_ttable);
 int n=lua_objlen(l,1);
 printf("n = %d\n",n);
 lua_pushstring(l,"ee");
 lua_rawseti(l,1,5); //t[n]=v,n为第三个参数,v是栈顶元素
 n=lua_objlen(l,1);
 printf("n = %d\n",n);
 int i;
 for(i=1;i<=n;i++){
 lua_rawgeti(l,1,i);
 printf("%s\n",lua_tostring(l,-1));
 }
 return 0;
}

lua脚本:

 

function gettable() 
  tb={ "aa","bb","cc","dd"} 
  return tb 
end 

运行输出的结果为:

n = 4 
n = 5 
aa 
bb 
cc 
dd 
ee