ecshop报错:Hacking attempt
程序员文章站
2022-05-03 21:53:44
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$.ajax({ url:"includes/lib_goods.php?is_ajax=1&act=get_recommend_goods", type:"GET", dataType:"text", data:{type:"newss",catscats}, beforeSend: function(){ alert("正在登录..."); }, success:function(json){ alert(json); if(json.succuss=1) { alert("success"); } else { alert("false"); } }, error: function(XMLHttpRequest, textStatus, errorThrown) { alert(XMLHttpRequest.status); alert(XMLHttpRequest.readyState); alert(textStatus); }, });
这是我dwt文件中调用lib_goods.php文件中的方法,不知道为什么一直抱错hacking attempt,不知道哪位帮忙看看?
回复讨论(解决方案)
hacking attempt 黑客行为
显然是判定你的来源非法,改用浏览器从网站上执行
includes/ 文件不能直接访问
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