JS获取URL中的参数数据_javascript技巧
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2022-04-28 09:29:34
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复制代码 代码如下:
function getParam(paramName) {
paramValue = "";
isFound = false;
if (this.location.search.indexOf("?") == 0 && this.location.search.indexOf("=") > 1) {
arrSource = unescape(this.location.search).substring(1, this.location.search.length).split("&");
i = 0;
while (i if (arrSource[i].indexOf("=") > 0) {
if (arrSource[i].split("=")[0].toLowerCase() == paramName.toLowerCase()) {
paramValue = arrSource[i].split("=")[1];
isFound = true;
}
}
i++;
}
}
return paramValue;
}
如:http://www.jb51.net/UserQuery.aspx?id=202
getParam("id")为202