欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  IT编程

angularJS1 url中携带参数的获取方法

程序员文章站 2023-11-11 17:13:22
index.html 从此界面跳转到a.html界面 ...

index.html 从此界面跳转到a.html界面

<!doctype html>
<html>

  <head>
    <meta charset="utf-8">
    <title>form demo</title>
    <meta name="viewport" content="width=device-width, minimum-scale=1.0, maximum-scale=1.0, user-scalable=0" />
    <script src="js/angular.min.1.6.0.js"></script>
  </head>

  <body ng-app="app" ng-controller="myctrl">

    <button ng-click="jump()" >点击跳转下一页</button>
    <br /><br />
    <a ng-href="a.html?name=xie&age=25&gender=nv" rel="external nofollow" >点击跳转下一页</a>
    </div>
  </body>

  <script>
    var app = angular.module('app', []);
    app.controller('myctrl', function($scope, $window) {
      $scope.jump = function() {
        $window.location.href = 'a.html?name=xie&age=25&gender=nv';
      }
    });
  </script>

</html>

a.html 跳转到的目标界面,在此界面获取url携带的参数:

<!doctype html>
<html>
  <head>
    <meta charset="utf-8">
    <meta name="viewport" content="width=device-width, minimum-scale=1.0, maximum-scale=1.0, user-scalable=0" />
    <script src="js/angular.min.1.6.0.js"></script>
    <title></title>
  </head>
  <body ng-app="myapp" ng-controller="myctrl" >
    <p>a.html</p>


  </body>
  <script>
  //url="http://168.33.222.69:8020/angularjs_demo/a.html?name=xie&age=25&gender=nv";
    var app=angular.module("myapp",[]);
    app.config(['$locationprovider', function($locationprovider) { 
     // $locationprovider.html5mode(true); 
     $locationprovider.html5mode({
     enabled: true,
     requirebase: false
    });
    }]);


    app.controller('myctrl', function($scope, $location) {


     console.log($location.search().name);
     console.log($location.search().age);
     console.log($location.search().gender);

    }); 

//打印结果:
//[web浏览器] "xie" 
//[web浏览器] "25" 
//[web浏览器] "nv" 


  </script>
</html>

以上这篇angularjs1 url中携带参数的获取方法就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持。