Codeforces Round #276 (Div. 2)_html/css_WEB-ITnose

链接:http://codeforces.com/contest/485

A. Factory

time limit per test

1 second

memory limit per test

256 megabytes

One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there werex details in the factory storage, then by the end of the day the factory has to produce (remainder after dividingx bym) more details. Unfortunately, no customer has ever bought any mythical detail, so all the details produced stay on the factory.

The board of directors are worried that the production by the given plan may eventually stop (that means that there will be а moment when the current number of details on the factory is divisible bym).

Given the number of details a on the first day and number m check if the production stops at some moment.

Input

The first line contains two integers a and m (1?≤?a,?m?≤?105).

Output

Print "Yes" (without quotes) if the production will eventually stop, otherwise print "No".

Sample test(s)

Input

1 5

Output

No

Input

3 6

Output

Yes

x每次加上对m取模的值，如果取模为0输出YES，如果值之前出现过，则进入循环输出No退出

#include #include int vis[100002];int main(){	int a, m;	scanf("%d %d", &a, &m);	memset(vis, 0, sizeof(vis));	while(true)	{		if(a == 0)		{			printf("Yes\n");			return 0;		}		if(vis[a])		{			printf("No\n");			return 0;		}		vis[a] = 1;		a = (a + a % m) % m;	}}

B. Valuable Resources

time limit per test

1 second

memory limit per test

256 megabytes

Many computer strategy games require building cities, recruiting army, conquering tribes, collecting resources. Sometimes it leads to interesting problems.

Let's suppose that your task is to build a square city. The world map uses the Cartesian coordinates. The sides of the city should be parallel to coordinate axes. The map contains mines with valuable resources, located at some points with integer coordinates. The sizes of mines are relatively small, i.e. they can be treated as points. The city should be built in such a way that all the mines are inside or on the border of the city square.

Building a city takes large amount of money depending on the size of the city, so you have to build the city with the minimum area. Given the positions of the mines find the minimum possible area of the city.

Input

The first line of the input contains number n ? the number of mines on the map (2?≤?n?≤?1000). Each of the nextn lines contains a pair of integersxi andyi ? the coordinates of the corresponding mine (?-?109?≤?xi,?yi?≤?109). All points are pairwise distinct.

Output

Print the minimum area of the city that can cover all the mines with valuable resources.

Sample test(s)

Input

20 02 2

Output

Input

20 00 3

Output

给几个点，让这几个点都在一个正方形上或者内部，求正方形的面积的最小值，最上减最下和最右减最左的最大值作为边长

#include #include #define ll long longusing namespace std;int main(){	int n;	ll x, y;	ll mu, md, ml, mr;	ll ans = 0;	mu = mr = -2147483646;	ml = md = 2147483647;	scanf("%d", &n);	for(int i = 0; i   
  

  

  

  

  

  
  
   
    
     
      
       C. Bits      
      
       
        time limit per test       
 1 second            
       
        memory limit per test       
 256 megabytes            
      
Let's denote as  the number of bits set ('1' bits) in the binary representation of the non-negative integer x.
      
You are given multiple queries consisting of pairs of integersl andr. For each query, find thex, such thatl?≤?x?≤?r, and is maximum possible. If there are multiple such numbers find the smallest of them.
          
      
       Input      
      
The first line contains integer n ? the number of queries (1?≤?n?≤?10000).
      
Each of the following n lines contain two integersli,?ri ? the arguments for the corresponding query (0?≤?li?≤?ri?≤?1018).
          
      
       Output      
      
For each query print the answer in a separate line.
          
      
       Sample test(s)      
      
       
        
         Input        
        
31 22 41 10
              
        
         Output        
        
137
                       
      
       Note      
      
The binary representations of numbers from 1 to 10 are listed below:
      
110?=?12
      
210?=?102
      
310?=?112
      
410?=?1002
      
510?=?1012
      
610?=?1102
      
710?=?1112
      
810?=?10002
      
910?=?10012
      
1010?=?10102
                
  

  
给一个区间，求区间里的数转化为二进制后拥有'1'个数最多的那个数，要是拥有'1'的数量相同，取最小的那个数输出。
  
直接从左端点对1进行或运算，构造出'1'最多且最小的数，直到值大于右端点
  

  
  
#include #define ll long longint main(){	int t;    scanf("%d", &t);      while(t--)    {          ll l, r, tmp, p = 1;           scanf("%I64d %I64d", &l, &r);        for(ll i = 0; i  r)            	break;              l = tmp;            p   
  

  

  

  

  
  
   
    D. Maximum Value   
   
    
     time limit per test    
 1 second      
    
     memory limit per test    
 256 megabytes      
   
You are given a sequence a consisting ofn integers. Find the maximum possible value of (integer remainder ofai divided byaj), where1?≤?i,?j?≤?n and ai?≥?aj.
    
   
    Input   
   
The first line contains integer n ? the length of the sequence (1?≤?n?≤?2·105).
   
The second line contains n space-separated integersai (1?≤?ai?≤?106).
    
   
    Output   
   
Print the answer to the problem.
    
   Sample test(s)  
  
   
    Input   
   
33 4 5
    
   Output  
  
  

  
找a[i]   

  
  
#include   int const MAX = 2000000 + 10;  int a[MAX];  int main()  {      int n, x, ans = 0;      scanf("%d",&n);        for(int i = 0; i  ans && a[j] > i)                      ans = a[j] % i;            printf("%d\n",ans);   } 
  

  

  

  

  
  
   
    
     
      
       Div.1 : D. Kindergarten      
      
       
        time limit per test       
 2 seconds            
       
        memory limit per test       
 256 megabytes            
      
In a kindergarten, the children are being divided into groups. The teacher put the children in a line and associated each child with his or her integer charisma value. Each child should go to exactly one group. Each group should be a nonempty segment of consecutive children of a line. A group's sociability is the maximum difference of charisma of two children in the group (in particular, if the group consists of one child, its sociability equals a zero).
      
The teacher wants to divide the children into some number of groups in such way that the totalsociability of the groups is maximum. Help him find this value.
          
      
       Input      
      
The first line contains integer n ? the number of children in the line (1?≤?n?≤?106).
      
The second line contains n integersai ? the charisma of thei-th child (?-?109?≤?ai?≤?109).
          
      
       Output      
      
Print the maximum possible total sociability of all groups.
          
      
       Sample test(s)      
      
       
        
         Input        
        
51 2 3 1 2
              
        
         Output        
              
        
         Input        
        
33 3 3
              
        
         Output        
                       
      
       Note      
      
In the first test sample one of the possible variants of an division is following: the first three children form a group with sociability 2, and the two remaining children form a group with sociability 1.
      
In the second test sample any division leads to the same result, the sociability will be equal to 0 in each group.
      

      
把一串数列分成若干组，每组的权值为该组中最大值与最小值的差，求所有组的权值和的最大值
      

      
      
#include #define ll long longint main(){    int n, t;     scanf ("%d", &n);    ll ans = 0, t1 = 0, t2 = 0;    for(int i = 0; i  t1) t1 = ans + t;        if (!i || ans - t > t2) t2 = ans - t;        ans = t1 - t > t2 + t ? t1 - t : t2 + t;    }    printf("%I64d\n", ans);}