C#中解析JSON数据，并获取到其中的值

1.应需求创建一个json字符串

　　string json = "[{'name':'张三','age':'20','data':{'id':100,'heigh':'180','weight':'90'}}]";

2.根据字符串的数据结构定义两个类：

　　public class user
        {
            public string name{ get; set; }
            public string age{ get; set; }
            public data data{ get; set; }
        }

　　public class data
        {
            public int id{ get; set; }
            public string heigh{ get; set; }
            public string weight{ get; set; }
        }

3.再main函数中进行操作，如下main函数：

　　static void main(string[] args)
        {
          string json = "[{'name':'张三','age':'20','data':{'id':100,'heigh':'180','weight':'90'}}]";
            list<user> jobinfolist = newtonsoft.json.jsonconvert.deserializeobject<list<user>>(json);

            foreach (info jobinfo in jobinfolist)
            {
                console.writeline("username:" + jobinfo.name);
                console.writeline("username:" + jobinfo.data.id);
            }
        }

　　public class user
        {
            public string name{ get; set; }
            public string age{ get; set; }
            public data data{ get; set; }
        }

　　public class data
        {
            public int id{ get; set; }
            public string heigh{ get; set; }
            public string weight{ get; set; }
        }