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C#中解析JSON数据,并获取到其中的值

程序员文章站 2022-06-28 20:49:40
1.应需求创建一个Json字符串 string json = "[{'Name':'张三','age':'20','Data':{'ID':100,'heigh':'180','weight':'90'}}]"; 2.根据字符串的数据结构定义两个类: public class User { publ ......

1.应需求创建一个json字符串

  string json = "[{'name':'张三','age':'20','data':{'id':100,'heigh':'180','weight':'90'}}]";

2.根据字符串的数据结构定义两个类:

  public class user
        {
            public string name{ get; set; }
            public string age{ get; set; }
            public data data{ get; set; }
        }

  public class data
        {
            public int id{ get; set; }
            public string heigh{ get; set; }
            public string weight{ get; set; }
        }

3.再main函数中进行操作,如下main函数:

  static void main(string[] args)
        {
          string json = "[{'name':'张三','age':'20','data':{'id':100,'heigh':'180','weight':'90'}}]";
            list<user> jobinfolist = newtonsoft.json.jsonconvert.deserializeobject<list<user>>(json);

            foreach (info jobinfo in jobinfolist)
            {
                console.writeline("username:" + jobinfo.name);
                console.writeline("username:" + jobinfo.data.id);
            }
        }

  public class user
        {
            public string name{ get; set; }
            public string age{ get; set; }
            public data data{ get; set; }
        }

  public class data
        {
            public int id{ get; set; }
            public string heigh{ get; set; }
            public string weight{ get; set; }
        }