Codeforces Round #254 (Div. 2)D（估计）_html/css_WEB-ITnose

D. DZY Loves FFT

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

DZY loves Fast Fourier Transformation, and he enjoys using it.

Fast Fourier Transformation is an algorithm used to calculate convolution. Specifically, if a, b and c are sequences with length n, which are indexed from 0 to n?-?1, and

We can calculate c fast using Fast Fourier Transformation.

DZY made a little change on this formula. Now

To make things easier, a is a permutation of integers from 1 to n, and b is a sequence only containing 0 and 1. Given a and b, DZY needs your help to calculate c.

Because he is naughty, DZY provides a special way to get a and b. What you need is only three integers n, d, x. After getting them, use the code below to generate a and b.

//x is 64-bit variable;function getNextX() {    x = (x * 37 + 10007) % 1000000007;    return x;}function initAB() {    for(i = 0; i     
 Operation x % y denotes remainder after division x by y. Function swap(x, y) swaps two values x and y.
      
    
     Input    
    
 The only line of input contains three space-separated integers n,?d,?x (1?≤?d?≤?n?≤?100000; 0?≤?x?≤?1000000006). Because DZY is naughty, x can't be equal to 27777500.
      
    
     Output    
    
 Output n lines, the i-th line should contain an integer ci?-?1.
      
    
     Sample test(s)    
    
     
      
       input      
      
3 1 1
          
      
       output      
      
132
          
      
       input      
      
5 4 2
          
      
       output      
      
22455
          
      
       input      
      
5 4 3
          
      
       output      
      
55554
               
   题意：RT  
  
   
  
   思路：因为b序列一定只含0或1，那么含0的是没有意义的  
  
   
  
               直接for就好了，然后用一个数组is[]记录前多少个b序列为1的位置  
  
   
  
               每次要找最大值的时候，如果is[]数组的个数小于一个常数，就枚举is数组  
  
   
  
               否则直接从大到小枚举最大值就好了