922. Sort Array By Parity II

题目

Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even.

Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even.

You may return any answer array that satisfies this condition.
Example 1:

Input: [4,2,5,7]
Output: [4,5,2,7]
Explanation: [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.

Note:

2 <= A.length <= 20000
A.length % 2 == 0
0 <= A[i] <= 1000

代码

class Solution:
    def sortArrayByParityII(self, A: List[int]) -> List[int]:
        B=[]
        C=[]
        D=[]
        for i in range(len(A)):
            if A[i]%2==0: 
                B.append(A[i])
            else:
                C.append(A[i])
        for i in range(0,len(A)//2):
                D.append(B[i])
                D.append(C[i])
        return D