922. Sort Array By Parity II
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2024-03-06 09:48:43
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Given an array A
of non-negative integers, half of the integers in A are odd, and half of the integers are even.
Sort the array so that whenever A[i]
is odd, i
is odd; and whenever A[i]
is even, i
is even.
You may return any answer array that satisfies this condition.
Example 1:
Input: [4,2,5,7] Output: [4,5,2,7] Explanation: [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.
Note:
2 <= A.length <= 20000
A.length % 2 == 0
0 <= A[i] <= 1000
解题思路:将奇偶数分成两个列表,然后用一个列表推成式返回结果
python代码
class Solution(object):
def sortArrayByParityII(self, A):
"""
:type A: List[int]
:rtype: List[int]
"""
ou = [i for i in A if i % 2]
ji = [i for i in A if not i % 2]
return [i for n in zip(ji, ou) for i in n]
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