生物信息学 几个程序

f = 'AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC'
for i in f:
    b = list(f)    # 把‘AAA’变成 ['A','A'',A']
    c = {}
    for i in b:
        c[i] = b.count(i)   # 把key 和value 写入字典，如 A：1
print (c.values())  # 最后的结果为 [20,12,21,17]

 

 

f = 'AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC'
counts = []
for i in ['A','C','G','T']:          # 把输出的顺序定好
    counts.append(f.count(i))
print ('\t'.join(map(str, counts)))  #map() 这里的意思是吧输出的[20,12,17,21]变为 20 12 17 21

f='AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC'
counts = []
for i in ['A','C','G','T']:
    
 counts.append(f.count(i))
print('\t'.join(map(str,counts)))

#join() 方法用于将(序列中的元素)以.join前指定的元素连接生成一个新的字符串。
# #map(str,counts):['20', '12', '17', '21']

DNAseq="TTGCAC"
mRNAseq=DNAseq.replace("T","U")
print(mRNAseq)

def transcribing_RNA(string):
    return string.replace("T", "U")
print(transcribing_RNA("GATGGAACTTGACTACGTAAATT"))

import operator
dict= {'a': 1, 'b': 4, 'c': 2, 'f' : 12}
s= sorted(dict.items(), key=operator.itemgetter(1),reverse=True)

print(s)