SQL 返回期间内的所有日期
程序员文章站
2023-12-09 19:43:21
复制代码 代码如下:select rownum as dateindex,to_date('20090701','yyyy-mm-dd')+ rownum-1 as dat...
复制代码 代码如下:
select rownum as dateindex,to_date('20090701','yyyy-mm-dd')+ rownum-1 as date_ from dual connect by level >= 1 and level <=(to_date('20090731','yyyy-mm-dd')-to_date('20090701','yyyy-mm-dd')+1)
result:
1 2009/07/01
2 2009/07/02
3 2009/07/03
4 2009/07/04
5 2009/07/05
6 2009/07/06
7 2009/07/07
8 2009/07/08
9 2009/07/09
10 2009/07/10
11 2009/07/11
12 2009/07/12
13 2009/07/13
14 2009/07/14
15 2009/07/15