cf1132E. Knapsack(搜索)
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2022-12-29 09:14:12
题意 "题目链接" Sol 看了status里面最短的代码。。感觉自己真是菜的一批。。直接爆搜居然可以过?。。但是现在还没终测所以可能会fst。。 cppp include define Pair pair define MP(x, y) make_pair(x, y) define fi firs ......
题意
sol
看了status里面最短的代码。。感觉自己真是菜的一批。。直接爆搜居然可以过?。。但是现在还没终测所以可能会fst。。
#include<bits/stdc++.h> #define pair pair<int, int> #define mp(x, y) make_pair(x, y) #define fi first #define se second #define int long long #define ll long long #define fin(x) {freopen(#x".in","r",stdin);} #define fout(x) {freopen(#x".out","w",stdout);} using namespace std; const int maxn = 1e6 + 10, mod = 1e9 + 7, inf = 1e9 + 10; const double eps = 1e-9; template <typename a, typename b> inline bool chmin(a &a, b b){if(a > b) {a = b; return 1;} return 0;} template <typename a, typename b> inline bool chmax(a &a, b b){if(a < b) {a = b; return 1;} return 0;} template <typename a, typename b> inline ll add(a x, b y) {if(x + y < 0) return x + y + mod; return x + y >= mod ? x + y - mod : x + y;} template <typename a, typename b> inline void add2(a &x, b y) {if(x + y < 0) x = x + y + mod; else x = (x + y >= mod ? x + y - mod : x + y);} template <typename a, typename b> inline ll mul(a x, b y) {return 1ll * x * y % mod;} template <typename a, typename b> inline void mul2(a &x, b y) {x = (1ll * x * y % mod + mod) % mod;} template <typename a> inline void debug(a a){cout << a << '\n';} template <typename a> inline ll sqr(a x){return 1ll * x * x;} inline int read() { char c = getchar(); int x = 0, f = 1; while(c < '0' || c > '9') {if(c == '-') f = -1; c = getchar();} while(c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar(); return x * f; } int w, a[9], ans; void dfs(int x, int now) { if(x == 9) {chmax(ans, now);return ;} for(int num = 9, v = min((w - now) / x, a[x]); num; num--, v--) dfs(x + 1, now + max((int)0, v * x)); } signed main() { w = read(); for(int i = 1; i <= 8; i++) a[i] = read(); dfs(1, 0); cout << ans; return 0; }
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