PAT基础编程题目-6-5 求自定类型元素的最大值
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2022-03-13 13:46:28
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PAT基础编程题目-6-5 求自定类型元素的最大值
题目详情
解答
C语言版
#include <stdio.h>
#define MAXN 10
typedef float ElementType;
ElementType Max(ElementType S[], int N);
int main()
{
ElementType S[MAXN];
int N, i;
scanf("%d", &N);
for (i = 0; i < N; i++)
scanf("%f", &S[i]);
printf("%.2f\n", Max(S, N));
return 0;
}
ElementType Max(ElementType S[], int N) {
ElementType max = S[0];
for (int i = 1; i < N; i++)
if (max < S[i])
max = S[i];
return max;
}
C++版
#include<iostream>
#include<iomanip>
using namespace std;
#define MAXN 10
typedef float ElementType;
ElementType Max(ElementType S[], int N);
int main() {
ElementType S[MAXN];
int N;
cin >> N;
for (int i = 0; i < N; i++)
cin >> S[i];
cout << fixed << setprecision(2) << Max(S, N);
return 0;
}
ElementType Max(ElementType S[], int N) {
ElementType max = S[0];
for (int i = 1; i < N; i++)
if (max < S[i])
max = S[i];
return max;
}
Java版
public class Main{
private static final int MAXN = 10;
private static float Max(float []S, int N) {
float max = S[0];
for (int i = 1; i < N; i++) {
if(max < S[i])
max = S[i];
}
return max;
}
public static void main(String[] args) {
int N =0;
float [] S = new float[MAXN];
Scanner scanner = new Scanner(System.in);
if (scanner.hasNext()) {
N = scanner.nextInt();
for (int i = 0; i < N; i++) {
S[i] = scanner.nextFloat();
}
}
scanner.close();
DecimalFormat decimalFormat = new DecimalFormat("#.00");
System.out.println(decimalFormat.format(Max(S, N)));
}
}
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