PAT基础编程题目-6-4 求自定类型元素的平均

题目详情

题目地址：https://pintia.cn/problem-sets/14/problems/736

解答

C语言版

#include <stdio.h>

#define MAXN 10
typedef float ElementType;

ElementType Average(ElementType S[], int N);

int main()
{
	ElementType S[MAXN];
	int N, i;

	scanf("%d", &N);
	for (i = 0; i < N; i++)
		scanf_s("%f", &S[i]);
	printf("%.2f\n", Average(S, N));

	return 0;
}

ElementType Average(ElementType S[], int N) {
	ElementType sum = 0;
	for (int i = 0; i < N; i++)
	{
		sum = sum + S[i];
	}
	return sum / N;
}

C++版

#include<iostream>
#include<iomanip>
using namespace std;
 
#define MAXN 10               //没有分号
typedef float ElementType;    //有分号

ElementType Average(ElementType S[], int N);

int main() {
	ElementType S[MAXN];
	int N;
	cin >> N;
	for (int i = 0; i < N; i++)
	{
		cin >> S[i];
	}
	cout << fixed << setprecision(2) << Average(S, N);
	return 0;
}

ElementType Average(ElementType S[], int N) {
	ElementType sum = 0;
	for (int i = 0; i < N; i++)
		sum = sum + S[i];
	return sum / N;
}

Java版

public class Main{
	
	private static final int MAXN = 10;
	
	private static float Average(float [] S, int N) {
		float sum = 0;
		//System.out.println(S.length);   //一直是10，不变
		for (int i = 0; i < N; i++) {
			sum = sum + S[i];
		}
		return sum/N;
	}
	

	public static void main(String[] args) {
		float [] S = new float[MAXN];
		int N = 0;
		Scanner scanner = new Scanner(System.in);
		if(scanner.hasNext()) {
			N = scanner.nextInt();
			for (int i = 0; i < N; i++) {
				S[i] = scanner.nextFloat();
			}
		}
		scanner.close();
		DecimalFormat decimalFormat = new DecimalFormat("#.00");
		System.out.println(decimalFormat.format(Average(S, N)));
	}

}

创作不易，喜欢的话加个关注点个赞，谢谢谢谢谢谢！