opencv+python识别七段数码显示器的数字(数字识别)
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2022-06-17 14:44:21
目录一、什么是七段数码显示器二、创建opencv数字识别器一、什么是七段数码显示器七段lcd数码显示器有很多叫法:段码液晶屏、段式液晶屏、黑白笔段屏、段码lcd液晶屏、段式显示器、tn液晶屏、段码液晶...
一、什么是七段数码显示器
七段lcd数码显示器有很多叫法:段码液晶屏、段式液晶屏、黑白笔段屏、段码lcd液晶屏、段式显示器、tn液晶屏、段码液晶显示器、段码屏幕、笔段式液晶屏、段码液晶显示屏、段式lcd、笔段式lcd等。
如下图,每个数字都由一个七段组件组成。
七段显示器总共可以呈现 128 种可能的状态:
我们要识别其中的0-9,如果用深度学习的方式有点小题大做,并且如果要进行应用还有很多前序工作需要进行,比如要确认识别什么设备的,怎么找到数字区域并进行分割等等。
二、创建opencv数字识别器
我们这里进行使用空调恒温器进行识别,首先整理下流程。
1、定位恒温器上的 lcd屏幕。
2、提取 lcd的图像。
3、提取数字区域
4、识别数字。
我们创建名称为recognize_digits.py的文件,代码如下。仅思路供参考(因为代码中的一些参数只适合测试图片)
# import the necessary packages from imutils.perspective import four_point_transform from imutils import contours import imutils import cv2 # define the dictionary of digit segments so we can identify # each digit on the thermostat digits_lookup = { (1, 1, 1, 0, 1, 1, 1): 0, (0, 0, 1, 0, 0, 1, 0): 1, (1, 0, 1, 1, 1, 1, 0): 2, (1, 0, 1, 1, 0, 1, 1): 3, (0, 1, 1, 1, 0, 1, 0): 4, (1, 1, 0, 1, 0, 1, 1): 5, (1, 1, 0, 1, 1, 1, 1): 6, (1, 0, 1, 0, 0, 1, 0): 7, (1, 1, 1, 1, 1, 1, 1): 8, (1, 1, 1, 1, 0, 1, 1): 9 } # load the example image image = cv2.imread("example.jpg")# # pre-process the image by resizing it, converting it to # graycale, blurring it, and computing an edge map image = imutils.resize(image, height=500) gray = cv2.cvtcolor(image, cv2.color_bgr2gray) blurred = cv2.gaussianblur(gray, (5, 5), 0) edged = cv2.canny(blurred, 50, 200, 255) # find contours in the edge map, then sort them by their # size in descending order cnts = cv2.findcontours(edged.copy(), cv2.retr_external, cv2.chain_approx_simple) cnts = imutils.grab_contours(cnts) cnts = sorted(cnts, key=cv2.contourarea, reverse=true) displaycnt = none # loop over the contours for c in cnts: # approximate the contour peri = cv2.arclength(c, true) approx = cv2.approxpolydp(c, 0.02 * peri, true) # if the contour has four vertices, then we have found # the thermostat display if len(approx) == 4: displaycnt = approx break # extract the thermostat display, apply a perspective transform # to it warped = four_point_transform(gray, displaycnt.reshape(4, 2)) output = four_point_transform(image, displaycnt.reshape(4, 2)) # threshold the warped image, then apply a series of morphological # operations to cleanup the thresholded image thresh = cv2.threshold(warped, 0, 255, cv2.thresh_binary_inv | cv2.thresh_otsu)[1] kernel = cv2.getstructuringelement(cv2.morph_ellipse, (1, 5)) thresh = cv2.morphologyex(thresh, cv2.morph_open, kernel) # find contours in the thresholded image, then initialize the # digit contours lists cnts = cv2.findcontours(thresh.copy(), cv2.retr_external, cv2.chain_approx_simple) cnts = imutils.grab_contours(cnts) digitcnts = [] # loop over the digit area candidates for c in cnts: # compute the bounding box of the contour (x, y, w, h) = cv2.boundingrect(c) # if the contour is sufficiently large, it must be a digit if w >= 15 and (h >= 30 and h <= 40): digitcnts.append(c) # sort the contours from left-to-right, then initialize the # actual digits themselves digitcnts = contours.sort_contours(digitcnts, method="left-to-right")[0] digits = [] # loop over each of the digits for c in digitcnts: # extract the digit roi (x, y, w, h) = cv2.boundingrect(c) roi = thresh[y:y + h, x:x + w] # compute the width and height of each of the 7 segments # we are going to examine (roih, roiw) = roi.shape (dw, dh) = (int(roiw * 0.25), int(roih * 0.15)) dhc = int(roih * 0.05) # define the set of 7 segments segments = [ ((0, 0), (w, dh)), # top ((0, 0), (dw, h // 2)), # top-left ((w - dw, 0), (w, h // 2)), # top-right ((0, (h // 2) - dhc) , (w, (h // 2) + dhc)), # center ((0, h // 2), (dw, h)), # bottom-left ((w - dw, h // 2), (w, h)), # bottom-right ((0, h - dh), (w, h)) # bottom ] on = [0] * len(segments) # loop over the segments for (i, ((xa, ya), (xb, yb))) in enumerate(segments): # extract the segment roi, count the total number of # thresholded pixels in the segment, and then compute # the area of the segment segroi = roi[ya:yb, xa:xb] total = cv2.countnonzero(segroi) area = (xb - xa) * (yb - ya) # if the total number of non-zero pixels is greater than # 50% of the area, mark the segment as "on" if total / float(area) > 0.5: on[i]= 1 # lookup the digit and draw it on the image digit = digits_lookup[tuple(on)] digits.append(digit) cv2.rectangle(output, (x, y), (x + w, y + h), (0, 255, 0), 1) cv2.puttext(output, str(digit), (x - 10, y - 10), cv2.font_hershey_simplex, 0.65, (0, 255, 0), 2) # display the digits print(u"{}{}.{} \u00b0c".format(*digits)) cv2.imshow("input", image) cv2.imshow("output", output) cv2.waitkey(0)
原始图片
边缘检测
识别的结果图片
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