C语言分装实现三子棋游戏详解
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2022-06-16 10:19:50
本文实例为大家分享了c语言分装实现三子棋游戏的具体代码,供大家参考,具体内容如下test.c --------------测试游戏的逻辑game.h------------关于游戏相关函数的声明gam...
本文实例为大家分享了c语言分装实现三子棋游戏的具体代码,供大家参考,具体内容如下
test.c --------------测试游戏的逻辑
game.h------------关于游戏相关函数的声明
game.c------------游戏相关函数的实现
game.h
#include<stdio.h> #include<stdlib.h> #include<time.h> //符号的定义 #define row 3 #define col 3 //函数声明 void initboard(char board[row][col], int row, int col); //初始化棋盘 void displayboard(char board[row][col], int row, int col); //打印棋盘 void playmove(char board[row][col], int row, int col); //玩家下 char iswin(char board[row][col], int row, int col); //判断输赢 void computermove(char board[row][col], int row, int col); //电脑下
game.c
#include"game.h" void initboard(char board[row][col], int row, int col) { int i = 0; int j = 0; for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { board[i][j] =' '; } } } void displayboard(char board[row][col], int row, int col) { int i = 0; int j = 0; for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { printf(" %c ", board[i][j]); if (j < col - 1) printf("|"); } printf("\n"); if (i < row - 1) { for (j = 0; j < col; j++) { printf("---"); if (j < col - 1) printf("|"); } printf("\n"); } } } void playmove(char board[row][col], int row, int col) { int x = 0; int y = 0; printf("玩家走,请输入坐标;>\n"); scanf("%d %d", &x, &y); while (1) { if (x >= 1 && x <= row && y >= 1 && y <= col) //判断坐标是否合法 { if (board[x-1][y-1] == ' ') //判断坐标是否被占用 { board[x-1][y-1] = '*'; break; } else printf("坐标已被占用,请重新输入\n"); } else printf("坐标非法,请重新输入\n"); } } void computermove(char board[row][col], int row, int col) { printf("电脑走\n"); while (1) { int x = rand() % row; int y = rand() % col; if (board[x][y] == ' ') //判断坐标是否被占用 { board[x][y] = '#'; break; } } } int isfull(char board[row][col], int row, int col) { int i = 0; int j = 0; for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { if(board[i][j] == ' ') return 0; //棋盘未满 } } return 1; // 棋盘满了 } char iswin(char board[row][col], int row, int col) { /*玩家赢 返回* 电脑赢 返回# 平局 返回p 继续游戏 返回q*/ int i = 0; int j = 0; for (i = 0; i < row; i++) { if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] != ' ') //判断行是否相等 return board[i][0]; } for (i = 0; i < col; i++) { if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[1][i] != ' ') //判断列是否相等 return board[1][i]; } if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[0][0] != ' ') //判断对角线是否相等 return board[1][1]; if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[0][2] != ' ') //判断对角线是否相等 return board[0][2]; int ret=isfull(board, row, col); // 判断是否平局(即判断棋盘是否已满) 此处row,col均为小写 //如果棋盘满了返回1,未满返回0 if (ret == 1) return 'p'; return 'q'; //游戏继续 }
test.c
#include"game.h" void menu() { printf("********************\n"); printf("*****1.play ********\n"); printf("*****0.exit ********\n"); } void game() { char board[row][col]; char ret=0; //接收游戏状态 initboard(board, row, col); //初始化棋盘 displayboard(board, row, col); //打印棋盘 while (1) { playmove(board, row, col); //玩家走 displayboard(board, row, col); ret=iswin(board, row, col); //判断输赢 if (ret != 'q') break; computermove(board, row, col); //电脑走 displayboard(board, row, col); ret = iswin(board, row, col); //判断输赢 if (ret != 'q') break; } if (ret == '*') printf("玩家胜\n"); if(ret=='#') printf("电脑胜\n"); if (ret == 'p') printf("平局\n"); displayboard(board, row, col); //展示棋盘 } int main() { int input = 0; srand((unsigned int)time(null)); do { menu(); printf("请选择;>\n"); scanf("%d", &input); switch (input) { case 1: { printf("开始游戏\n"); game(); break; } case 0: { printf("退出游戏\n"); break; } default: { printf("选择错误,请重新选择;>\n"); } } } while (input); return 0; }
代码实现结果图
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