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PAT A1107. Social Clusters (30)

程序员文章站 2022-06-11 11:18:29
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  1. Social Clusters (30)

时间限制
1000 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
When register on a social network, you are always asked to specify your hobbies in order to find some potential friends with the same hobbies. A “social cluster” is a set of people who have some of their hobbies in common. You are supposed to find all the clusters.

Input Specification:

Each input file contains one test case. For each test case, the first line contains a positive integer N (<=1000), the total number of people in a social network. Hence the people are numbered from 1 to N. Then N lines follow, each gives the hobby list of a person in the format:

Ki: hi[1] hi[2] … hi[Ki]

where Ki (>0) is the number of hobbies, and hi[j] is the index of the j-th hobby, which is an integer in [1, 1000].

Output Specification:

For each case, print in one line the total number of clusters in the network. Then in the second line, print the numbers of people in the clusters in non-increasing order. The numbers must be separated by exactly one space, and there must be no extra space at the end of the line.

Sample Input:
8
3: 2 7 10
1: 4
2: 5 3
1: 4
1: 3
1: 4
4: 6 8 1 5
1: 4
Sample Output:
3
4 3 1

#include<cstdio>
#include<algorithm>
#include<vector>
using namespace std;

const int N=1010;

int father[N];
int isRoot[N]={0};
int course[N]={0};

int findFather(int x){
    int a=x;
    while(x!=father[x]){
        x=father[x];
    }
    //路径压缩
    while(a!=father[a]){
        int z=a;
        a=father[a];
        father[z]=x;
    }
    return x;
}

void Union(int a,int b){//让a所在群的所有人 称呼 b所在群的大哥 为 大哥
    int faA=findFather(a);
    int faB=findFather(b);
    if(faA!=faB){
        father[faA]=faB;
    }
}

void init(int n){
    for(int i=1;i<=n;i++){
        father[i]=i;
        isRoot[i]=false;
    }
}

bool cmp(int a,int b){
    return a>b;
}

int main(){
    int n,k,h;
    scanf("%d",&n);
    init(n);//初始化每个人的大哥是自己
    for(int i=1;i<=n;i++){//对每个人
        scanf("%d:",&k);
        for(int j=0;j<k;j++){
            scanf("%d",&h);
            if(course[h]==0)
                course[h]=i;//兴趣群h的大哥是第一个加入的人
            Union(i,findFather(course[h]));//因为i在兴趣群h中 那么 让i所在群所有人 称呼 兴趣群h的大哥的大哥 为大哥
        }
    }
    for(int i=1;i<=n;i++){
        isRoot[findFather(i)]++;//对每个人 寻找其大哥  大哥x被叫了几次就表示有isRoot[x]个小弟
    }
    int ans=0;
    for(int i=1;i<=n;i++){
        if(isRoot[i]!=0){
            ans++;
        }
    }
    printf("%d\n",ans);
    sort(isRoot+1,isRoot+n+1,cmp);
    for(int i=1;i<=ans;i++){
        printf("%d",isRoot[i]);
        if(i<ans)printf(" ");
    }
    return 0;
}

PAT A1107. Social Clusters (30)