C# 使用this.invoke和sleep暂时解决UI假死问题，保证background worker.dowork下的线程同步，又不会丢失太多速度

            int intStart = 0;
            for (int j = 0; j <= newPaths.Length - 1; j++)
            {
                File.Copy(newPaths[j], newPaths[j].Replace(sourceFolderName, destFolderName1), true);
                File.Copy(newPaths[j], newPaths[j].Replace(sourceFolderName, destFolderName2), true);
                Console.WriteLine(newPaths[j]);
                Console.WriteLine(newPaths[j].Replace(sourceFolderName, destFolderName1));
                Console.WriteLine("---copy to input_pass and output----");
                intStart += 1;
                //to do: use Invoke to keep sync on this thread, but it will cause the pace slower
                if (intStart % 50 == 0) //to do: temperatory solution, still need to deal with the thread
                {
                    this.Invoke(new Action(() =>
                    {
                         bgWorker1.ReportProgress(intStart, "copying");
                    }));  
                }
                System.Threading.Thread.Sleep(1); //to do: temperatory solution, still need to deal with the thread