Python制作简单的剪刀石头布游戏

关于程序相关的

• 您可以反复玩游戏，直到选择停止为止。
• 该程序跟踪获胜情况。
• 大小写无关紧要（即rock与rock相同）。
• 如果您输入的内容无效，程序会一直提示您，直到您输入有效的内容。

对项目进行编码的步骤：

1. 创建一个简单的单轮游戏版本，我们不执行正确的输入。
2. 如果输入了无效的内容，则添加while循环可重新提示用户输入选择。
3. 使用while循环让用户反复播放，并使用变量来跟踪得分。

程序代码

import random

input("welcome to rock, paper, scissors! press enter to start.")
print()
user_wins = 0
computer_wins = 0

choices = ["rock", "paper", "scissors"]

while true:
 random_index = random.randint(0,2)
 cpu_choice = choices[random_index]

 user_choice = input("rock, paper, or scissors? ").lower()
 while user_choice not in choices:
  user_choice = input("that is not a valid choice. please try again: ").lower()
 
 print()
 print("your choice:", user_choice)
 print("computer's choice:", cpu_choice)
 print()

 if user_choice == 'rock':
  if cpu_choice == 'rock':
   print("it's a tie!")
  elif cpu_choice == 'scissors':
   print("you win!")
   user_wins+=1
  elif cpu_choice == 'paper':
   print("you lose!")
   computer_wins+=1
 elif user_choice == 'paper':
  if cpu_choice == 'paper':
   print("it's a tie!")
  elif cpu_choice == 'rock':
   print("you win!")
   user_wins+=1
  elif cpu_choice == 'scissors':
   print("you lose!")
   computer_wins+=1
 elif user_choice == 'scissors':
  if cpu_choice == 'scissors':
   print("it's a tie!")
  elif cpu_choice == 'paper':
   print("you win!")
   user_wins+=1
  elif cpu_choice == 'rock':
   print("you lose!")
   computer_wins+=1

 print()
 print("you have "+str(user_wins)+" wins")
 print("the computer has "+str(computer_wins)+" wins")
 print()

 repeat = input("play again? (y/n) ").lower()
 while repeat not in ['y', 'n']:
  repeat = input("that is not a valid choice. please try again: ").lower()
 
 if repeat == 'n':
  break

 print("\n----------------------------\n")

运行效果：

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