java实现简单石头剪刀布游戏

本文实例为大家分享了java实现简单石头剪刀布游戏的具体代码，供大家参考，具体内容如下

问题描述

alice, bob和cindy一起玩猜拳的游戏。和两个人的猜拳类似,每一轮,他们会从石头、剪刀、布中各自选一个出拳,基本的胜负规则是石头赢剪刀、剪刀赢布、布赢石头。如果一轮中正好可以分成胜负两边,则负边的每个人要支付给胜边的每个人一块钱。如果无法分成胜负两边,则都不出钱。比如,如果alice出石头,而bob和cindy都出布,则alice要分支付bob和cindy一块钱。再如,如果alice出石头, bob出剪刀, cindy出布,则都不出钱。他们三人共进行了n轮游戏,请问最后每个人净赚多少钱?即赚的钱减去支付的钱是多少?

代码

package ring1270.pra.java01;
import java.util.scanner;
/**
 * finger-guessing game: * n:number of games * a: person a's money * b: person b's money * c: person c's money * 0: stand for stone * 1: stand for scissor * 2: stand for cloth * rule1: two persons give the same result means game over * rule2: the money add 1 everytime which win * rule3:the money less 1 everytime which fail * */public class d_fingerguessinggame {
  public static void main(string[] args) {
    int a = 0;
    int b = 0;
    int c = 0;
    scanner scanner = new scanner(system.in);
    system.out.printf("the number of game:");
    int n = scanner.nextint();
    stringbuffer stringbuffer = new stringbuffer();
    for (int i = 0; i <= n; i++) {
      string s = scanner.nextline();
      char[] d = s.tochararray();
      for (int j = 0; j < d.length; j++) {
        //a and b success
 if (d[0] == d[1] && d[0] != d[2]) {
          if ('0' == d[0] && '1' == d[2]) {
            a++;
            b++;
            c -= 2;
          }
          else if ('1' == d[0] && '2' == d[2]) {
            a++;
            b++;
            c -= 2;
          }
          else if ('2' == d[0] && '0' == d[2]) {
            a++;
            b++;
            c -= 2;
          }else {
            a--;
            b--;
            c += 2;
          }
        }
        // a and c success
 if (d[0] == d[2] && d[0] != d[1]) {
          if ('0' == d[0] && '1' == d[1]) {
            a++;
            b -= 2;
            c++;
          }
          else if ('1' == d[0] && '2' == d[1]) {
            a++;
            b -= 2;
            c++;
          }
          else if ('2' == d[0] && '0' == d[1]) {
            a++;
            b -= 2;
            c++;
          }else {
            a--;
            b += 2;
            c--;
          }
        }
        // c and b success
 if (d[1] == d[2] && d[1] != d[0]) {
          if ('0' == d[1] && '1' == d[0]) {
            a -= 2;
            b++;
            c++;
          }
          else if ('1' == d[1] && '2' == d[0]) {
            a -= 2;
            b++;
            c++;
          }
          else if ('2' == d[1] && '0' == d[0]) {
            a -= 2;
            b++;
            c++;
          }
          else {
            a += 2;
            b--;
            c--;
          }
        }
        break;
      }
    }
    system.out.println(a);
    system.out.println(b);
    system.out.println(c);
  }
}

运行截图

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