FOJ 1889 龟兔赛跑

一，问题描述

二，问题分析

思路很简单，只需要根据题意比较龟兔的路程即可，兔子：（总时间 - 睡觉时间）*速度    乌龟：总时间 * 速度

三，代码解答

#include<iostream>
#include<cstdio>
#include<vector>
using namespace std;

struct Game
{
	int allTime;		//比赛时间
	int sleepTime;	//兔子睡觉时间
	int rspeed;		//兔子时速
	int tspeed;		//乌龟时速
};

int main() {
	int num;			//比赛组数
	cin >> num;
	vector<Game> games(num);
	vector<int> out(num);
	for (int i = 0; i < num; i++) {
		cin >> games[i].allTime >> games[i].sleepTime >> games[i].rspeed >> games[i].tspeed;
		if ((games[i].allTime - games[i].sleepTime) * games[i].rspeed > games[i].allTime*games[i].tspeed) {		//兔子胜
			out[i] = 0;
		}
		else if ((games[i].allTime - games[i].sleepTime) * games[i].rspeed < games[i].allTime * games[i].tspeed)	//乌龟胜
		{
			out[i] = 1;
		}
		else
		{
			out[i] = -1;
		}
	}
	for (int i = 0; i < num; i++) {
		cout << out[i] << endl;
	}

	return 0;

}