浙大版《C语言程序设计（第3版）》题目集 习题10-1 判断满足条件的三位数 (15分)

#include <stdio.h>
#include <math.h>
int search(int n);
int main()
{
    int number;
    scanf("%d", &number);
    printf("count=%d\n", search(number));
    return 0;
}
int search(int n)
{
    int i, count, j, digit[3], temp, k;
    count = 0;
    for (i = 101; i <= n; i++)
    {
        temp = i;
        for (j = 10; j < 32; j++)
        {
            if (pow(j, 2) == temp)
            {
                k = 0;
                while (temp)
                {
                    digit[k] = temp % 10;
                    temp /= 10;
                    k++;
                }
                if (digit[0] == digit[1] || digit[0] == digit[2] || digit[1] == digit[2])
                {
                    count++;
                }
            }
        }
    }
    return count;
}