566. Reshape the Matrix
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2022-05-31 18:54:58
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In MATLAB, there is a very useful function called ‘reshape’, which can reshape a matrix into a new one with different size but keep its original data.
You’re given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.
The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.
If the ‘reshape’ operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.
Example 1:
Example 2:
题解:
package com.leetcode;
import java.util.Arrays;
public class MatrixReshape {
public static void main(String[] args) {
int[][] nums = { { 1, 2 },
{ 3, 4 } };
System.out.println(Arrays.deepToString(nums));
int[][] ans = matrixReshape(nums, 4, 1);
System.out.println(Arrays.deepToString(ans));
ans = matrixReshape(nums, 1, 4);
System.out.println(Arrays.deepToString(ans));
ans = matrixReshape(nums, 2, 4);
System.out.println(Arrays.deepToString(ans));
}
public static int[][] matrixReshape(int[][] nums, int r, int c) {
if (r * c != nums.length * nums[0].length)
return nums;
int[][] ans = new int[r][];
for (int i = 0; i < r; i++)
ans[i] = new int[c];
for (int i = 0; i < r; i++) {
for (int j = 0; j < c; j++) {
int k = i * c + j; // ans中的第k个元素
int a = k / nums[0].length; // ans中的第k个元素在nums中对应的下标
int b = k - a * nums[0].length;
ans[i][j] = nums[a][b];
}
}
return ans;
}
}
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解决ValueError: cannot reshape array of size 2328750 into shape (200,234,1)