c# Newtonsoft.Json 常用方法总结

1 实体类的 json 序列化和反序列化

我们以如下的 person 类举例，其中包含了常用的数据类型：

public class person
{
 public int id { get; set; }

 public string name { get; set; }

 public datetime birthday { get; set; }

 public bool isvip { get; set; }
 
 public float account { get; set; }

 public string[] favorites { get; set; }
 
 public string remark { get; set; }
}

创建一个 person 实例：

person person = new person
{
 id = 1,
 name = "张三",
 birthday = datetime.parse("2000-01-02"),
 isvip = true,
 account = 12.34f,
 favorites = new string[] { "吃饭", "睡觉" }
};

1.1 json 序列化

返回不缩进的 json 字符串

jsonconvert.serializeobject(person);

{"id":1,"name":"张三","birthday":"2000-01-02t00:00:00","isvip":true,"account":12.34,"favorites":["吃饭","睡觉"],"remark":null}

返回缩进的 json 字符串

jsonconvert.serializeobject(person, formatting.indented);

{
 "id": 1,
 "name": "张三",
 "birthday": "2000-01-02t00:00:00",
 "isvip": true,
 "account": 12.34,
 "favorites": [
  "吃饭",
  "睡觉"
 ],
 "remark": null
}

1.2 将不缩进的 json 字符串转成缩进形式

private string jsonindentation(string str)
{
 //string str = jsonconvert.serializeobject(entity);
 jsonserializer serializer = new jsonserializer();
 textreader tr = new stringreader(str);
 jsontextreader jtr = new jsontextreader(tr);
 object obj = serializer.deserialize(jtr);
 if (obj != null)
 {
  stringwriter textwriter = new stringwriter();
  jsontextwriter jsonwriter = new jsontextwriter(textwriter)
  {
   formatting = formatting.indented,
   indentation = 4,
   indentchar = ' '
  };
  serializer.serialize(jsonwriter, obj);
  return textwriter.tostring();
 }
 else
 {
  return str;
 }
}

或者：

private string jsonindentation(string json)
{
 jobject obj = jobject.parse(json);
 return obj.tostring();
}

1.3 其他设置

jsonserializersettings settings = new jsonserializersettings();
// 设置日期格式
settings.dateformatstring = "yyyy-mm-dd";
// 忽略空值
settings.nullvaluehandling = nullvaluehandling.ignore;
// 缩进
settings.formatting = formatting.indented;

jsonconvert.serializeobject(person, settings);

返回：

{
 "id": 1,
 "name": "张三",
 "birthday": "2000-01-02",
 "isvip": true,
 "account": 12.34,
 "favorites": [
 "吃饭",
 "睡觉"
 ]
}

1.4 json 反序列化

jsonconvert.deserializeobject<person>(json);

2 jobject 使用

2.1 创建对象

jobject obj = new jobject();
obj.add("id", 1);
obj.add("name", "张三");
obj.add("birthday", datetime.parse("2000-01-02"));
obj.add("isvip", true);
obj.add("account", 12.34f);
// 创建数组
jarray array = new jarray();
array.add(new jvalue("吃饭"));
array.add(new jvalue("睡觉"));
obj.add("favorites", array);
obj.add("remark", null);

2.2 jobject 中添加数组

上例中的代码可以简化为：

jarray array = new jarray("吃饭", "睡觉");

2.3 从 json 字符串创建 jobject

string json = "{\"id\":1,\"name\":\"张三\",\"birthday\":\"2000-01-02t00:00:00\",\"isvip\":true,\"account\":12.34,\"favorites\":[\"吃饭\",\"睡觉\"],\"remark\":null}";

jobject obj = jobject.parse(json);

2.4 从 entity 创建 jobject

jobject obj = jobject.fromobject(person);

用匿名对象创建 jobject

jobject obj = jobject.fromobject(new { name = "jack", age = 18 });

//显示
{
 "name": "jack",
 "age": 18
}

用初始化器

jobject obj = new jobject()
{
 { "name", "jack" },
 { "age", 18 }
};

2.5 获取值

int id;
if (obj["id"] != null)
 id = obj["id"].value<int>();

2.6 获取数组

newtonsoft.json.linq 不支持直接获取数组，但是可以获取 list，然后再转化为数组。

string[] favorites;
if (obj["favorites"] != null)
 favorites = obj["favorites"].value<list<string>>().toarray();

以上就是c# newtonsoft.json 常用方法总结的详细内容，更多关于c# newtonsoft.json的资料请关注其它相关文章！