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C#判断单词个数方法总结

程序员文章站 2023-12-18 23:48:10
方法一: 判断英文单词个数: using system; namespace findword { class program {...

方法一:

判断英文单词个数:

using system;

namespace findword
{
  class program
  {
    static void main(string[] args)
    {
      string space = " ";
      string str = "hello world" + space;
      int count = 0;
      bool start = false;
      for (int i=0;i<str.length;i++)
      {
        if (char .isletter(str[i]))
        {
          start = true;
        }
        if (!char.isletter(str[i])&&start)
        {
          count++;
          start = false;
        }
        
      }
      console.writeline(count);
      console.readline();
    }
  }
}

方法二:

c#统计英文字符串中单词个数思路如下:

1.使用的hashtable(高效)集合,记录每个单词出现的次数

2.采用arraylist对hashtable中的keys按字母序排列

3.排序使用插入排序(稳定)

public void statisticswords(string path) {
  if (!file.exists(path))
  {
  console.writeline("文件不存在!");
  return;
  }
  hashtable ht = new hashtable(stringcomparer.ordinalignorecase);
  streamreader sr = new streamreader(path, system.text.encoding.utf8);
  string line = sr.readline();
  string[] wordarr = null;
  int num = 0;
  while (line.length > 0)
  {
  //  matchcollection mc = regex.matches(line, @"\b[a-z]+", regexoptions.compiled | regexoptions.ignorecase);
  //foreach (match m in mc)
  //{
  //  if (ht.containskey(m.value))
  //  {
  //    num = convert.toint32(ht[m.value]) + 1;
  //    ht[m.value] = num;
  //  }
  //  else
  //  {
  //    ht.add(m.value, 1);
  //  }
  //}
  //line = sr.readline();
  wordarr = line.split(' ');
  foreach (string s in wordarr)
  {
  if (s.length == 0)
  continue;
  //去除标点
  line = regex.replace(line, @"[\p{p}*]", "", regexoptions.compiled);
  //将单词加入哈希表
  if (ht.containskey(s))
  {
  num = convert.toint32(ht[s]) + 1;
  ht[s] = num;
  }
  else
  {
  ht.add(s, 1);
  }
  }
  line = sr.readline();
  }
arraylist keyslist = new arraylist(ht.keys);
  //对hashtable中的keys按字母序排列
  keyslist.sort();
  //按次数进行插入排序【稳定排序】,所以相同次数的单词依旧是字母序
  string tmp = string.empty;
  int valuetmp = 0;
  for (int i = 1; i < keyslist.count; i++)
  {
  tmp = keyslist[i].tostring();
  valuetmp = (int)ht[keyslist[i]];//次数
  int j = i;
  while (j > 0 && valuetmp > (int)ht[keyslist[j - 1]])
  {
  keyslist[j] = keyslist[j - 1];
  j--;
  }
  keyslist[j] = tmp;//j=0
  }
  //打印出来
  foreach (object item in keyslist)
  {
  console.writeline((string)item + ":" + (string)ht[item]);
  }
  }

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