Python实现简单http服务器
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2022-05-15 13:32:08
写一个python脚本，实现简单的http服务器功能：
1.浏览器中输入网站地址：172.20.52.163:20014
2.server接到浏览器的请求后，读取本地的...
写一个python脚本，实现简单的http服务器功能：
1.浏览器中输入网站地址：172.20.52.163:20014
2.server接到浏览器的请求后，读取本地的index.html文件的内容，回发给浏览器
代码实现
server.py
#!/usr/bin/python
import socket
import signal
import errno
from time import sleep
def httpresponse(header,whtml):
f = file(whtml)
contxtlist = f.readlines()
context = ''.join(contxtlist)
response = "%s %d\n\n%s\n\n" % (header,len(context),context)
return response
def siginthander(signo,frame):
print 'get signo# ',signo
global runflag
runflag = false
global lisfd
lisfd.shutdown(socket.shut_rd)
strhost = "172.20.52.163"
host = strhost #socket.inet_pton(socket.af_inet,strhost)
port = 20014
httpheader = '''''\
http/1.1 200 ok
context-type: text/html
server: python-slp version 1.0
context-length: '''
lisfd = socket.socket(socket.af_inet,socket.sock_stream)
lisfd.bind((host, port))
lisfd.listen(2)
signal.signal(signal.sigint,siginthander)
runflag = true
while runflag:
try:
confd,addr = lisfd.accept()
except socket.error as e:
if e.errno == errno.eintr:
print 'get a except eintr'
else:
raise
continue
if runflag == false:
break;
print "connect by ",addr
data = confd.recv(1024)
if not data:
break
print data
confd.send(httpresponse(httpheader,'index.html'))
confd.close()
else:
print 'runflag#',runflag
print 'done'
index.html
<html> <head> <title>python server</title> </head> <body> <h1>hello python</h1> <p>welcom to the python world</br> </body> </html>
测试
测试结果：
root@cloud2:~/slp/pythonlearning/socket# ./server_v1.py
connect by ('172.20.52.110', 6096)
get / http/1.1
host: 172.20.52.163:20014
connection: keep-alive
accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
user-agent: mozilla/5.0 (windows nt 5.1) applewebkit/537.36 (khtml, like gecko) chrome/33.0.1750.154 safari/537.36
accept-encoding: gzip,deflate,sdch
accept-language: zh-cn,zh;q=0.8,en;q=0.6
浏览器
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