ctf-BugkuCTF-crypto

1.滴答~滴

很容易看出这是摩斯加密，直接解密即可，注意格式

#encode=utf-8
s='-... -.- -.-. - ..-. -- .. ... -.-. '
codebook = {
    'A':".-",'B':"-...",'C':"-.-.",'D':"-..",'E':".",'F':"..-.",'G':"--.",'H':"....",'I':"..",'J':".---",'K':"-.-",'L':".-..",'M':"--",'N':"-.",'O':"---",'P':".--.",'Q':"--.-",'R':".-.",'S':"...",'T':"-",'U':"..-",'V':".--",'W':".--",'X':"-..-",'Y':"-.--",'Z':"--..",'1':".----",'2':"..---",'3':"...--",'4':"....-",'5':".....",'6':"-....",'7':"--...",'8':"---..",'9':"----.",'0':"-----",'.':".━.━.━",'?':"..--..",'!':"-.-.--",'(':"-.--.",'@':".--.-.",':':"---...",'=':"-...-",'-':"-....-",')':"-.--.-",'+':".-.-.",',':"--..--",'\'':".----.",'_':"..--.-",'$':"...-..-",';':"-.-.-.",'/':"-..-.",'\"':".-..-.",'&':"...."
}

cipher=""
ss = s.split(" ")
for c in ss:
    for k in codebook.keys():
        if codebook[k] == c:
             cipher+=k
             break
    else:
        cipher+=c
print(cipher)

2.聪明的小羊

栅栏加密，根据开头位key可知是以8个字符来分段

miwen="KYsd3js2E{a2jda}"
str1=""
for i in xrange(0,8):
    k=0
    while k*8+i<len(miwen):
        str1+=miwen[k*8+i]
        k+=1

print str1

3.ok

Ook解密，直接在https://www.splitbrain.org/services/ook在线解密即可

4.这不是摩斯密码

打开文件，是Brainfuck加密，在https://www.splitbrain.org/services/ook在线解密即可

5.简单加密

看题中字符毫无规律，但字符又可见，猜测可能是ascii的移位加密，尝试未发现比较流畅的句子，却发现比较像base64加密后的字符串，拿去解密发现答案

miwen="e6Z9i~]8R~U~QHE{RnY{QXg~QnQ{^XVlRXlp^XI5Q6Q6SKY8jUAA"
mingwen=""
sign=True

for j in xrange(1,256):
    for i in miwen:
        mingwen=mingwen+chr((ord(i)+j)%128)
    for i in mingwen:
        if ord(i)>126 or ord(i)<33:
            sign=False
            break
    if sign:
        print mingwen
        print j
        
    mingwen=""
    sign=True

6.一段Base64

打开根据题意，应该会用base64解码，于是打开文件，看到结尾的“==”，于是将其中的字符复制出来进行base64解码，得到结果如图：

看到这样编码的形式，使用js的unescape解码，在网页控制台输入console.log(unescape("\....“))得到结果：

将16进制ascii码转为字符，在网页控制台输入console.log("\x.....")得到结果结果如图所示

 明显是unicode编码，在网页控制台输入console.log("\u.....")得到结果结果如图所示

 由提示可知是10进制ascii码转为字符

s="38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,48,59,38,35,120,51,50,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,48,59,38,35,120,51,56,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,57,59,38,35,120,51,55,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,48,59,38,35,120,51,51,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,51,59,38,35,120,51,55,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,53,59,38,35,120,51,53,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,54,59,38,35,120,51,54,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,57,59,38,35,120,51,57,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,49,59,38,35,120,51,54,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,48,59,38,35,120,51,50,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,57,59,38,35,120,51,53,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,49,59,38,35,120,51,54,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,48,59,38,35,120,51,50,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,57,59,38,35,120,51,57,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,53,59,38,35,120,51,48,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,52,59,38,35,120,51,56,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,52,59,38,35,120,51,57,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,53,59,38,35,120,51,53,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,52,59,38,35,120,51,57,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,53,59,38,35,120,51,53,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,49,59,38,35,120,51,51,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,49,59,38,35,120,51,57,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,49,59,38,35,120,51,48,59,38,35,120,51,49,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,51,59,38,35,120,51,55,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,53,59,38,35,120,51,53,59,38,35,120,51,98,59,38,35,120,50,54,59,38,35,120,50,51,59,38,35,120,51,54,59,38,35,120,51,56,59,38,35,120,51,98,59"
list1=s.split(",")
str1=""
for i in list1:
    str1+=chr(int(i))

print str1

可获得 &#x开头的字符串,将&#x删除只留下16进制ascii，再转化为字符串

s="&#102&#x3b;&#108&#x3b;&#97&#x3b;&#103&#x3b;&#37&#x3b;&#55&#x3b;&#66&#x3b;&#99&#x3b;&#116&#x3b;&#102&#x3b;&#95&#x3b;&#116&#x3b;&#102&#x3b;&#99&#x3b;&#50&#x3b;&#48&#x3b;&#49&#x3b;&#55&#x3b;&#49&#x3b;&#55&#x3b;&#113&#x3b;&#119&#x3b;&#101&#x3b;&#37&#x3b;&#55&#x3b;&#68&#x3b"
str1=""
list1=s.split(";")
for i in list1:
    str1+=chr(int(i[3:5],16))
print str1

 可获得 &#开头的字符串,将&#删除只留下10进制ascii，再转化为字符串flag%7Bctf_tfc201717qwe%7D，再使用urldecode解码可得结果

 

7..!?

Ook解密,直接在https://www.splitbrain.org/services/ook在线解密即可

8.+[]-

Brainfuck加密，在https://www.splitbrain.org/services/ook在线解密即可

9.

仔细看题，我们获得密文，**还有一个加密规则，加密规则的编号应该是和**的数字相关，应该是将密文加密后放在**对应的那一行上，而每一行的字符前后都有“<",且中间由26个字母随机组成的字符，猜测是移位加密，只不过不是按照正常字母顺序加密，而是根据给定字母顺序加密，

list1=["ZWAXJGDLUBVIQHKYPNTCRMOSFE","KPBELNACZDTRXMJQOYHGVSFUWI","BDMAIZVRNSJUWFHTEQGYXPLOCK","RPLNDVHGFCUKTEBSXQYIZMJWAO","IHFRLABEUOTSGJVDKCPMNZQWXY","AMKGHIWPNYCJBFZDRUSLOQXVET","GWTHSPYBXIZULVKMRAFDCEONJQ","NOZUTWDCVRJLXKISEFAPMYGHBQ","QWATDSRFHENYVUBMCOIKZGJXPL","WABMCXPLTDSRJQZGOIKFHENYVU","XPLTDAOIKFZGHENYSRUBMCQWVJ","TDSWAYXPLVUBOIKZGJRFHENMCQ","BMCSRFHLTDENQWAOXPYVUIKZGJ","XPHKZGJTDSENYVUBMLAOIRFCQW"]
minlist=[]
key=[2,5,1,3,6,4,9,7,8,14,10,13,11,12]
minstr="HCBTSXWCRQGLES"
i=0
#根据key调整规则字母顺序和规则顺序以便做移位解密
while i<14:
    j=list1[(key[i]-1)].find(minstr[i])
    str2=list1[(key[i]-1)][j:]+list1[(key[i]-1)][:j]
    minlist.append(str2)
    i=i+1
i=0
str1=""
#将移位的所有情况输出
while i<len(minlist[0]):
    for j in minlist:
        str1+=j[i]
    print str1
    str1=""
    i=i+1
    str1=""

可在其中找到一条相对通顺的句子即为答案

10.告诉你个秘密

题目给了一串16进制的数，尝试移位解密，失败，但发现直接转出的字符串由常见字符组成，且长度为48，猜测是不是base64解密，尝试得到r5yG lp9I BjM tFhBT6uh y7iJ QsZ bhM，看一下键盘，发现键盘加密，解密得到结果

11.来自宇宙的信号

找到密码表即可解出，找不到那只能凉凉了（附密码表）