python批量创建指定名称的文件夹

本文实例为大家分享了python批量创建指定名称的文件夹具体代码，供大家参考，具体内容如下

继删除多余文件之后，做了一些数据处理，需要重新保存数据，但文件夹的名称又不能改

所以只能创建新的文件夹，换个路径用之前的文件夹名

import os 
import glob
 
#txt文件生成一次就好，或者用os.walk遍历需要的文件夹名称路径
def mk_text(txt_path):
 folders = glob.glob(txt_path + '/*_1')
 writetext = open('f:/my_data/brats18_training/test.txt', 'w')
 for files in folders:
 if len(files) <= 0:
  continue
 writetext.write(os.sep + files + ', ' + '\n')
 writetext.close()
 
 
def mkdir(mk_path): 
 test = []
 name = []
 
# =============================================================================
# 或者用下面的程序把三个循环替换
# for line in open('f:/my_data/brats18_training/test.txt', 'r'):
#  test.append(line)
#  
# for filename in test:
# filename = filename.strip()
# filename = filename.rstrip(',')
# if os.path.basename(filename)[0:7] == 'brats18':
#  name = os.path.join(mk_path + '/' +os.path.basename(filename))
#  isexists = os.path.exists(name)
#  if not isexists:
#  os.mkdir(name)
#  print(name +'successed')
#  else:
#  print(name + 'this is this content')
# =============================================================================
 for line in open('f:/my_data/brats18_training/test.txt', 'r'):
 test.append(line)
 for filename in test: 
 filename = filename.strip()
 filename = filename.rstrip(",") 
 if os.path.basename(filename)[0:7]=='brats18':
  name.append(os.path.join(mk_path + '/' + os.path.basename(filename)))
  
 for generate_path in name:
 #print(generate_path)
 isexists = os.path.exists(generate_path)
 if not isexists:
  os.mkdir(generate_path)
  print(generate_path + '创建成功')
  #千万不要用return
 else:
  print(generate_path + ' there is this content')
 
  
path = 'f:/my_data/hgg'  
mk_path = "h:/data/hgg"
mkdir(mk_path)
mk_txt(path)

小编再为大家分享一段：在指定目录批量创建文件夹的python实现代码：

目标文件夹为：l:\zj_landsat\lc81220442013221lgn00\waterquality_pca\results
目录l:\zj_landsat下有大量影像文件。

import os

rootdir = "l:\zj_landsat"
name1 = "waterquality_pca"
name2 = "results"
folder_name = "pca_4_bands"

def listdir(rootdir):
 dir1 = []
 for dirpath, dirnames, filenames in os.walk(rootdir):
  for dir in dirnames: 
   dir1.append(os.path.join(rootdir,dir[0:21]))#lc81220442013221lgn00的长度为21  
 return dir1
 print("done!")

dirlist = listdir(rootdir)[0:104]#104为104个影像文件夹数量
dir1 = []
dir2 = []
for dir in dirlist:
 dir1 = os.path.join(''.join(dir),name1)
 dir2 = os.path.join(dir1,name2)
 dir3 = os.path.join(dir2,folder_name)
 if not os.path.exists(dir3):
  os.mkdir(os.path.join(dir3))

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持。