php总是报错，大家帮小弟我看下代码

php总是报错，大家帮我看下代码

if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
if (PHP_VERSION $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
}

$theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

switch ($theType) {
case "text":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "long":
case "int":
$theValue = ($theValue != "") ? intval($theValue) : "NULL";
break;
case "double":
$theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
break;
case "date":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "defined":
$theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
break;
}
return $theValue;
}
}

mysql_select_db($database_test, $test);
$query_test = "SELECT * FROM test";
$test = mysql_query($query_test, $test) or die(mysql_error());
$row_test = mysql_fetch_assoc($test);
$totalRows_test = mysql_num_rows($test);
?>

id

name

pass

$result1 = mysql_query("SELECT * FROM test where id while($row1=mysql_fetch_array($result1))
{
$id=trim($row1[id]);
$name=trim($row1[name]);
$pass=trim($row1[pass]);
echo
"





";
}

?>

id	name	pass
$id	$name	$pass

mysql_free_result($test);
?>[code=PHP][/code]
=============================
报错：
Notice: Use of undefined constant id - assumed 'id' in D:\xampp\htdocs\vest\index.php on line 68

Notice: Use of undefined constant name - assumed 'name' in D:\xampp\htdocs\vest\index.php on line 69

Notice: Use of undefined constant pass - assumed 'pass' in D:\xampp\htdocs\vest\index.php on line 70

68、69、70这三行是

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