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leetcode 68 文本左右对齐/ textJustification

程序员文章站 2022-05-12 10:05:57
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题目描述:

leetcode 68 文本左右对齐/ textJustification

    比较繁琐的模拟题,写了三四个小时,无参考硬干出来了,一开始还比较高兴,结果查看别人的示范样例发现20行就搞出来了。。思路大体上都差不多:一行一行的处理,第一步确认每一行能装多少个元素,确认完之后再根据不同情况分配空格,对最后一行要特殊处理。代码如下:

示范代码:

class Solution {
public:
    vector<string> fullJustify(vector<string>& words, int L) {
        vector<string> res;
        for(int i = 0, k, l; i < words.size(); i += k) {
            for(k = l = 0; i + k < words.size() && l + words[i+k].size() <= L - k; k++) {//L-k因为每一个单词都有一个空格,l是一行中字符的长度
                l += words[i+k].size();
            }
            string tmp = words[i];
            for(int j = 0; j < k - 1; j++) {
                if(i + k >= words.size()) tmp += " ";//最后一行,只加一个空格
                else tmp += string((L - l) / (k - 1) + (j < (L - l) % (k - 1)), ' ');//不是最后一行,补齐空格,最左边(L - l) % (k - 1)个单词后要比之后的多一个空格
                tmp += words[i+j+1];
            }
            tmp += string(L - tmp.size(), ' ');//最后一行,末尾补空格
            res.push_back(tmp);
        }
        return res;
    }
};

我的。。。:

class Solution {
	public:
		vector<string> fullJustify(vector<string>& words, int maxWidth) {
			int i = 0 ;
			vector<string> res;
			int wordsCnt,prev,blankCnt,blankPlaceLeft,blankPlace,temp,blankgap,total,p,j,tempLeft;
			prev = 0;
			while(i < words.size()){
				temp = 0;
				string out;
				while(i < words.size()){
					if(temp != 0 && words[i].size() + temp + 1 > maxWidth){
						break;
					}
					if(temp == 0 && temp + words[i].size() <= maxWidth){
						temp += words[i].size();
						i++;
					}
					if(temp != 0 && temp + 1 + words[i].size() <= maxWidth){
						temp += 1;
						temp += words[i].size();
						i++;
					}
				}
				i = i - 1;//当前行最大数量
				total = i - prev + 1;
				wordsCnt = 0;
				for(j = prev; j <= i; j++) wordsCnt += word[j].size();
				if(i == words.size() - 1){//最后一行
					if(total == 1){
						//res[t] += words[i];
						out += words[i];
						out.append(maxWidth - wordsCnt,' ');
						res.push_back(out);
						return res;
					}
					else{
						for(p = prev ;p <= i - 1;p++){
							out += words[p];
							out.append(1,' ');
						}
						out += words[p];
						out.append(maxWidth - wordsCnt - total + 1,' ');
					}
					res.push_back(out);
					return res;
				}
				blankCnt = maxWidth - wordsCnt;//空格占有的位置数//3
				blankPlace = total - 1;//2
				if(blankPlace >= 2) blankPlaceLeft = blankCnt % blankPlace;//1
				if(blankPlace >= 2) blankgap = blankCnt / blankPlace;//1
				if(total == 1){
					//res[t] += words[i];
					out += words[i];
					//res[t] += //blankCnt 个空格
					out.append(blankCnt,' ');
					res.push_back(out);
				}
				else if(total == 2){
					//res[t] += words[prev];
					out += words[prev];
					//res[t] += //blankCnt 个空格
					out.append(blankCnt,' ');
					//res[t] += words[i];
					out += words[i];
					res.push_back(out);
				}
				else{// 单行 字符个数 大于等于3时
					if(blankPlaceLeft == 0){
						for(p = prev ;p <= i - 1;p++){
						    out += words[p];
						out.append(blankgap,' ');
						}
					}
					else{ //b
						tempLeft = 0;
						for(p = prev ;p <= i - 1;p++){
							out += words[p];
							if(tempLeft < blankPlaceLeft){
								out.append(1 + blankgap,' ');
								tempLeft ++;
							}
							else{
								out.append(blankgap,' ');
							}
						}
					}
					out += words[p];
					res.push_back(out);
			}
				prev = i + 1;
				i++;
			}
	  }
	};

不知不觉就写了那么大一堆,感觉自己还是 too young,还要多学习一个