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检测一个函数是否是JavaScript原生函数的小技巧_javascript技巧

程序员文章站 2022-05-11 18:53:13
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在我的开发工作中经常会遇到需要判断一个函数是否是JavaScript原生函数的情况,有时候这是一个很必要的工作,你需要知道这个函数是浏览器自身提供的,还是由第三方封装、伪装成原生函数。当然,最好的方法是考察执行这个函数的toString方法的返回值。

The JavaScript

完成这个任务的方法非常简单:

复制代码 代码如下:

function isNative(fn) {
return (/\{\s*\[native code\]\s*\}/).test('' + fn);
}

toString方法会返回这个方法的字符串形式,然后用正则表达式判断里面包含的字符。

更强悍的方法

Lodash的创始人John-David Dalton找到了一个更佳的方案:

复制代码 代码如下:

;(function() {

// Used to resolve the internal `[[Class]]` of values
var toString = Object.prototype.toString;

// Used to resolve the decompiled source of functions
var fnToString = Function.prototype.toString;

// Used to detect host constructors (Safari > 4; really typed array specific)
var reHostCtor = /^\[object .+?Constructor\]$/;

// Compile a regexp using a common native method as a template.
// We chose `Object#toString` because there's a good chance it is not being mucked with.
var reNative = RegExp('^' +
// Coerce `Object#toString` to a string
String(toString)
// Escape any special regexp characters
.replace(/[.*+?^${}()|[\]\/\\]/g, '\\$&')
// Replace mentions of `toString` with `.*?` to keep the template generic.
// Replace thing like `for ...` to support environments like Rhino which add extra info
// such as method arity.
.replace(/toString|(function).*?(?=\\\()| for .+?(?=\\\])/g, '$1.*?') + '$'
);

function isNative(value) {
var type = typeof value;
return type == 'function'
// Use `Function#toString` to bypass the value's own `toString` method
// and avoid being faked out.
? reNative.test(fnToString.call(value))
// Fallback to a host object check because some environments will represent
// things like typed arrays as DOM methods which may not conform to the
// normal native pattern.
: (value && type == 'object' && reHostCtor.test(toString.call(value))) || false;
}

// export however you want
module.exports = isNative;
}());


现在你也看到了,很复杂,但更强大。当然,这不是为了做安全防护,它只是给你提供是否是原生函数的相关信息。