python怎么判断字符串中出现次数最多的字母？

我的代码：

import string

def checkio(text):
    
    text = text.lower()
    
    if 0 < len(text) and len(text) <=10**5:
        return max(string.ascii_lowercase, key=text.count)
    #replace this for solution
    else:
        False

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    #assert checkio("Hello World!") == "l", "Hello test"
    #assert checkio("How do you do?") == "o", "O is most wanted"
    #assert checkio("One") == "e", "All letter only once."
    #assert checkio("Oops!") == "o", "Don't forget about lower case."
    #assert checkio("AAaooo!!!!") == "a", "Only letters."
    #assert checkio("abe") == "a", "The First."
    #print("Start the long test")
    #assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
    print("The local tests are done.")

大神的代码;

import string

def checkio(text):
    """
    We iterate through latyn alphabet and count each letter in the text.
    Then 'max' selects the most frequent letter.
    For the case when we have several equal letter,
    'max' selects the first from they.
    """
    text = text.lower()
    return max(string.ascii_lowercase, key=text.count)