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python3获取当前年份的每个月第一天和最后一天日期

程序员文章站 2022-05-10 19:37:57
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python3获取从一月到当前月份每月的首天和最后一天日期

1.代码

import datetime, calendar
from datetime import timedelta

# 获取当前年份每个月的首天和最后一天,本月最后一天取本日数据
def getYearMonthsDay():
    result = {}
    # 获取当前年份
    thisYear = datetime.date.today().year
    # 获取当前月份
    thisMonth = datetime.date.today().month
    # 获取当前天
    thisDay = datetime.date.today().day
    for x in range(1, thisMonth + 1):
        monthRange = calendar.monthrange(thisYear, x)[1]
        startDay = str(thisYear) + "-" + str(x).zfill(2) + "-01"
        endDay = str(thisYear) + "-" + str(x).zfill(2) + "-"
        #如果不想本月取最后一天取当前日期,可不做判断,直接用endDay = endDay + str(monthRange).zfill(2)
        if x == thisMonth:
            endDay = endDay + str(thisDay).zfill(2)
        else:
            endDay = endDay + str(monthRange).zfill(2)
        result[str(x)] = [startDay, endDay]
    return result

2.测试结果
测试代码:

print("今天是:" + str(datetime.date.today()))
print("获取跨度日期:" + str(getYearMonthsDay()))

结果:

今天是:2019-12-04
获取跨度日期:{'1': ['2019-01-01', '2019-01-31'], '2': ['2019-02-01', '2019-02-28'], '3': ['2019-03-01', '2019-03-31'], '4': ['2019-04-01', '2019-04-30'], '5': ['2019-05-01', '2019-05-31'], '6': ['2019-06-01', '2019-06-30'], '7': ['2019-07-01', '2019-07-31'], '8': ['2019-08-01', '2019-08-31'], '9': ['2019-09-01', '2019-09-30'], '10': ['2019-10-01', '2019-10-31'], '11': ['2019-11-01', '2019-11-30'], '12': ['2019-12-01', '2019-12-04']}
相关标签: python2