如何以数组中对象的某个字段为基准重新排列数组的内容
程序员文章站
2022-05-10 19:14:56
...
比如下面是我从数据库中读取出来的数据,然后我想以suppliers_id为基准重新排列这个数组,有什么比较好的方法?
[
{
cart_id: "6",
suppliers_id: "1",
goods_name: "商品1",
},
{
cart_id: "7",
suppliers_id: "1",
goods_name: "商品2",
}
{
cart_id: "7",
suppliers_id: "1",
goods_name: "商品3",
}
]
变成
[
//suppliers_id
1:
[
{
cart_id: "6",
suppliers_id: "1",
goods_name: "商品1",
},
{
cart_id: "7",
suppliers_id: "1",
goods_name: "商品3",
}
]
//suppliers_id
2:
[
{
cart_id: "7",
suppliers_id: "1",
goods_name: "商品2",
}
]
]
回复内容:
比如下面是我从数据库中读取出来的数据,然后我想以suppliers_id为基准重新排列这个数组,有什么比较好的方法?
[
{
cart_id: "6",
suppliers_id: "1",
goods_name: "商品1",
},
{
cart_id: "7",
suppliers_id: "1",
goods_name: "商品2",
}
{
cart_id: "7",
suppliers_id: "1",
goods_name: "商品3",
}
]
变成
[
//suppliers_id
1:
[
{
cart_id: "6",
suppliers_id: "1",
goods_name: "商品1",
},
{
cart_id: "7",
suppliers_id: "1",
goods_name: "商品3",
}
]
//suppliers_id
2:
[
{
cart_id: "7",
suppliers_id: "1",
goods_name: "商品2",
}
]
]
看到标签是 php
表示无能为力。
如果是在前端处理你倒是可以用 sort(function(a,b){})
这种思路来。
使用PHP的uksort函数,这货可以接收两个参数
$arr = [
{c:"213"}
,
{c:"dadad"}]
function compare_func($a, $b){
return $a=>c - $b=>c;
}
uksrot($arr,"compare_func" );