javascript - PHP和Ajax做的分页跳转,可是出不来。望大神能看看
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2022-05-10 13:51:59
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想做一个ajax局部刷新分页跳转，可是不知道为什么用ajax接受的数据在页面
上显示出来总是这么一句话MySql ErrorNo database selected 然后我做了几个测试
发现echo"111111";echo"22222";echo"3333"echo"4444";只有4444输出！PHP我不是很懂
所以想麻烦大神们看下是怎么回事！小弟在此谢过了！
上显示出来总是这么一句话MySql ErrorNo database selected 然后我做了几个测试
发现echo"111111";echo"22222";echo"3333"echo"4444";只有4444输出！PHP我不是很懂
所以想麻烦大神们看下是怎么回事！小弟在此谢过了！
" . $row['id'] . " " . $htmlmsg . "";
}
$msg = "" . $msg . "
"; // Content for Data
**echo "3333333333333333333333";**
/* --------------------------------------------- */
$query_pag_num = "SELECT COUNT(*) AS count FROM content";
$result_pag_num = mysql_query($query_pag_num);
$row = mysql_fetch_array($result_pag_num);
$count = $row['count'];
$no_of_paginations = ceil($count / $per_page);
**echo "2222222222";**
/* ---------------Calculating the starting and endign values for the loop----------------------------------- */
if ($cur_page >= 7) {
$start_loop = $cur_page - 3;
if ($no_of_paginations > $cur_page + 3)
$end_loop = $cur_page + 3;
else if ($cur_page $no_of_paginations - 6) {
$start_loop = $no_of_paginations - 6;
$end_loop = $no_of_paginations;
} else {
$end_loop = $no_of_paginations;
}
} else {
$start_loop = 1;
if ($no_of_paginations > 7)
$end_loop = 7;
else
$end_loop = $no_of_paginations;
}
/* ----------------------------------------------------------------------------------------------------------- */
$msg .= "
";
// FOR ENABLING THE FIRST BUTTON
if ($first_btn && $cur_page > 1) {
$msg .= "- First
";
} else if ($first_btn) {
$msg .= "- First
";
}
// FOR ENABLING THE PREVIOUS BUTTON
if ($previous_btn && $cur_page > 1) {
$pre = $cur_page - 1;
$msg .= "- Previous
";
} else if ($previous_btn) {
$msg .= "- Previous
";
}
for ($i = $start_loop; $i {$i}";
else
$msg .= "- {$i}
";
}
// TO ENABLE THE NEXT BUTTON
if ($next_btn && $cur_page Next";
} else if ($next_btn) {
$msg .= "- Next
";
}
// TO ENABLE THE END BUTTON
if ($last_btn && $cur_page Last";
} else if ($last_btn) {
$msg .= "- Last
";
}
$goto = "";
$total_string = "Page " . $cur_page . " of $no_of_paginations";
$msg = $msg . "
" . $goto . $total_string . ""; // Content for pagination
**echo $msg;**
**echo "1111111111111";**
}
?>
以上是代码
回复内容：
想做一个ajax局部刷新分页跳转，可是不知道为什么用ajax接受的数据在页面
上显示出来总是这么一句话MySql ErrorNo database selected 然后我做了几个测试
发现echo"111111";echo"22222";echo"3333"echo"4444";只有4444输出！PHP我不是很懂
所以想麻烦大神们看下是怎么回事！小弟在此谢过了！
" . $row['id'] . " " . $htmlmsg . "";
}
$msg = "" . $msg . "
"; // Content for Data
**echo "3333333333333333333333";**
/* --------------------------------------------- */
$query_pag_num = "SELECT COUNT(*) AS count FROM content";
$result_pag_num = mysql_query($query_pag_num);
$row = mysql_fetch_array($result_pag_num);
$count = $row['count'];
$no_of_paginations = ceil($count / $per_page);
**echo "2222222222";**
/* ---------------Calculating the starting and endign values for the loop----------------------------------- */
if ($cur_page >= 7) {
$start_loop = $cur_page - 3;
if ($no_of_paginations > $cur_page + 3)
$end_loop = $cur_page + 3;
else if ($cur_page $no_of_paginations - 6) {
$start_loop = $no_of_paginations - 6;
$end_loop = $no_of_paginations;
} else {
$end_loop = $no_of_paginations;
}
} else {
$start_loop = 1;
if ($no_of_paginations > 7)
$end_loop = 7;
else
$end_loop = $no_of_paginations;
}
/* ----------------------------------------------------------------------------------------------------------- */
$msg .= "
";
// FOR ENABLING THE FIRST BUTTON
if ($first_btn && $cur_page > 1) {
$msg .= "- First
";
} else if ($first_btn) {
$msg .= "- First
";
}
// FOR ENABLING THE PREVIOUS BUTTON
if ($previous_btn && $cur_page > 1) {
$pre = $cur_page - 1;
$msg .= "- Previous
";
} else if ($previous_btn) {
$msg .= "- Previous
";
}
for ($i = $start_loop; $i {$i}";
else
$msg .= "- {$i}
";
}
// TO ENABLE THE NEXT BUTTON
if ($next_btn && $cur_page Next";
} else if ($next_btn) {
$msg .= "- Next
";
}
// TO ENABLE THE END BUTTON
if ($last_btn && $cur_page Last";
} else if ($last_btn) {
$msg .= "- Last
";
}
$goto = "";
$total_string = "Page " . $cur_page . " of $no_of_paginations";
$msg = $msg . "
" . $goto . $total_string . ""; // Content for pagination
**echo $msg;**
**echo "1111111111111";**
}
?>
以上是代码
看一下文档啊 少年 点击链接
既然你是用的mysqli，三楼说的没错，选择一下数据库，mysqli是mysqli_select_db()这个，链接里有，你看下。
mysql 和mysqli混用！
上面用的$conn=mysqli_connect("localhost","root","","info");
下面用mysql_query($query_pag_data)
要不改成
$conn=mysql_connect("localhost","root","","info");
mysql_query($conn,"SET NAMES 'utf8'");
这个报错是因为没有选择数据库呀，你在连接之后执行一下mysqli_query('use database')，database是你的数据库，另外像楼上说的，别mysqli和mysql混杂用，php官方已经放弃mysql扩展了，用pdo或者mysqli