帮我看一下，着么输都是验证码错误！

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用户名&nbsp&nbsp:


密&nbsp&nbsp码&nbsp&nbsp:


确认密码:


邮&nbsp&nbsp箱&nbsp&nbsp: placeholder="请输入正确的邮箱格式" name="email">

验证码&nbsp&nbsp：

require('03.php');
?>

我已阅读并同意该协议
《book》条款

002.php
if(isset($_POST['submit'])) {
session_start();
$checkstr = $_SESSION['yzm']; //使用$_SESSION变量获取03.php页面上的验证码
$str = $_POST['check']; //用户输入的字符串
if (strcasecmp($str, $checkstr) != 0) //不区分大小写进行比较
echo "";
else {
$conn = mysql_connect("localhost", "root", "123456");
mysql_query("set names 'utf8'");
mysql_select_db("book", $conn);
$username = $_POST["username"];
$password = $_POST["psw1"];
$email = $_POST["email"];
$sql = "insert into register(username,password,email) VALUES ('$username','$password','$email')";
$result = mysql_query($sql);
if ($result) {
session_start();
$_SESSION['username'] = $username;
print("

");
}
}
}
else echo"非法访问";
?>



03.php
function a($type, $length ,$clear){
$nums=range(0,9);
$xxzm=range('a','z');
$dxzm=range('A','Z');
$igorne=array('0','o','1','l');
$chars=array();
if($type==1)
$chars=$nums;
if($type==2)
$chars=array_merge($nums,$xxzm);
if($type==3)
$chars=array_merge($nums,$xxzm,$dxzm);
if($clear==true)
$chars=array_diff($chars,$igorne);
$keys=array_rand($chars,$length);
$code="";
foreach($keys as $key)
$code=$code.$chars[$key];
return $code;
}
$yzm=a(3,5,true);
$_SESSION['yzm']=$yzm;
echo $yzm;
?>

回复讨论(解决方案)

if(psw1.value!=psw2.value)
psw2.setCustomValidity("两次密码不一致");
return false;
没有{ }？好久没用JS不太记得了。

js的代码是没错的，问题是出在验证码的验证上！

03.php 中没有 session_start();

虽然验证是对了，但是出来了个警告Notice:A session had already been started -ignoring session_star( ) in 002.php
这又是什么原因呢

警告是说session_start的时候session已经start了，所以第二次跳过了
也就是说一次流程执行到了两次session_start
原因就是脚本2里有两个session_start，把第二个删掉就行了