Codeigniter列出错误的邮件地址

大家好，我在用CodeIgniter PHP foreach 过一个email地址的表单，发现一些不符合正则表达式要求的Email，列出来以便改进。

难题在于难以将结果以object形式列出来。

代码：

PHP:

    $this->db->where('status', 'subscribed');
    $email_preliminary=$this->db->select('email')->get('user'); 

    $email_raw = array();

    foreach ($email_preliminary->result() as $row):

        $email_to_test=$row->email;

        if(filter_var($email_to_test, FILTER_VALIDATE_EMAIL)||preg_match('/\d*[1-9]\d*/', $email_to_test))
        {
            $email_raw[] = $email_to_test;
        }

        else{

        }
    endforeach;

    $record_raw=array_unique($email_raw);

    $data['record'] = json_decode (json_encode ($record_raw), FALSE);

    $this->load->view('login&signup/signup_test_view', $data);
}

HTML Signup_test_view里，我有:

  result() as $row): ?>

email; ?>

错误信息为：

Call to a member function result() on a non-object in D:\views\login&signup\signup_test_view.php

但我不是已经用下面这行代码把array转变成object了吗:

  $data['record'] = json_decode (json_encode ($record_raw), FALSE);

谢谢！

---

更新：

有同学建议把view里的代码改成

  email; ?>

也试了，错误信息仍为：
A PHP Error was encountered

Severity: Notice

Message: Trying to get property of non-object

Filename: login&signup/signup_test_get_wrong_email_view.php

回复内容：

大家好，我在用CodeIgniter PHP foreach 过一个email地址的表单，发现一些不符合正则表达式要求的Email，列出来以便改进。

难题在于难以将结果以object形式列出来。

代码：

PHP:

    $this->db->where('status', 'subscribed');
    $email_preliminary=$this->db->select('email')->get('user'); 

    $email_raw = array();

    foreach ($email_preliminary->result() as $row):

        $email_to_test=$row->email;

        if(filter_var($email_to_test, FILTER_VALIDATE_EMAIL)||preg_match('/\d*[1-9]\d*/', $email_to_test))
        {
            $email_raw[] = $email_to_test;
        }

        else{

        }
    endforeach;

    $record_raw=array_unique($email_raw);

    $data['record'] = json_decode (json_encode ($record_raw), FALSE);

    $this->load->view('login&signup/signup_test_view', $data);
}

HTML Signup_test_view里，我有:

  result() as $row): ?>

email; ?>

错误信息为：

Call to a member function result() on a non-object in D:\views\login&signup\signup_test_view.php

但我不是已经用下面这行代码把array转变成object了吗:

  $data['record'] = json_decode (json_encode ($record_raw), FALSE);

谢谢！

---

更新：

有同学建议把view里的代码改成

  email; ?>

也试了，错误信息仍为：
A PHP Error was encountered

Severity: Notice

Message: Trying to get property of non-object

Filename: login&signup/signup_test_get_wrong_email_view.php

array不也是蛮好用的么，那你需要一个把array转换成object ?

$obj = (object) $array;