MYSQL实现排名及查询指定用户排名功能（并列排名功能）实例代码

前言

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表结构：

create table test.testsort (
 
id int(11) not null auto_increment,
 
uid int(11) default 0 comment '用户id',
 
score decimal(10, 2) default 0.00 comment '分数',
 
primary key (id)
 
)
 
engine = innodb
 
auto_increment = 1
 
character set utf8
 
collate utf8_general_ci
 
comment = '测试排序'
 
row_format = dynamic;

思路：可以先排序，再对结果进行编号；也可以先查询结果，再排序编号。

说明：

@rownum := @rownum + 1 中 := 是赋值的作用，这句话的意思是先执行@rownum + 1，然后把值赋给@rownum；

(select @rownum := 0) r 这句话的意思是设置rownum字段的初始值为0，即编号从1开始。

实现排名：

方法一：

select t.*, @rownum := @rownum + 1 as rownum
 
from (select @rownum := 0) r, (select * from testsort order by score desc) as t;

方法二：

select t.*, @rownum := @rownum + 1 as rownum
 
from (select @rownum := 0) r, testsort as t
 
order by t.score desc;

结果：

 

查看指定用户排名：

方法一：

select b.* from
 
(
 
select t.*, @rownum := @rownum + 1 as rownum
 
from (select @rownum := 0) r,
 
(select * from testsort order by score desc) as t
 
) as b where b.uid = 222;

方法二:

select b.* from
 
(
 
select t.*, @rownum := @rownum + 1 as rownum
 
from (select @rownum := 0) r, testsort as t
 
order by t.score desc
 
) as b where b.uid = 222;

结果：

实现并列排名（相同分数排名相同）：

select
 
obj.uid,
 
obj.score,
 
case
 
when @rowtotal = obj.score then
 
@rownum
 
when @rowtotal := obj.score then
 
@rownum :=@rownum + 1
 
when @rowtotal = 0 then
 
@rownum :=@rownum + 1
 
end as rownum
 
from
 
(
 
select
 
uid,
 
score
 
from
 
testsort
 
order by
 
score desc
 
) as obj,
 
(select @rownum := 0 ,@rowtotal := null) r

查询指定用户并列排名:

select total.* from
 
(select
 
obj.uid,
 
obj.score,
 
case
 
when @rowtotal = obj.score then
 
@rownum
 
when @rowtotal := obj.score then
 
@rownum :=@rownum + 1
 
when @rowtotal = 0 then
 
@rownum :=@rownum + 1
 
end as rownum
 
from
 
(
 
select
 
uid,
 
score
 
from
 
testsort
 
order by
 
score desc
 
) as obj,
 
(select @rownum := 0 ,@rowtotal := null) r) as total where total.uid = 222;

总结

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