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把list集合的内容写入到Xml中,通过XmlDocument方式写入Xml文件中

程序员文章站 2022-05-07 16:37:02
List list = new List { new Person{Name="张三",Age=20,Email="zs@zhansan.com"}, new Person{Name="李四",Age=30,Email="ls@lisi.com"}, new Pers ......

 

list<person> list = new list<person>
{
new person{name="张三",age=20,email="zs@zhansan.com"},
new person{name="李四",age=30,email="ls@lisi.com"},
new person{name="王五",age=22,email="ww@wangwu.com"},
new person{name="赵柳",age=20,email="xl@zhaoliou.com"},
new person{name="玄武",age=20,email="xw@xuanwu.com"},
new person{name="白虎",age=20,email="bh@baihu.com"},
};

//实例化xmldocument对象
xmldocument xmldoc = new xmldocument();

//增加一个xml文档声明

xmldeclaration xmldeclaration = xmldoc.createxmldeclaration("1.0", "utf-8", null);

//创建xml文档根节点

xmlelement xmlelement = xmldoc.createelement("list");

//添加到xml文档中
xmldoc.appendchild(xmlelement);

//循环添加

for (int i = 0; i < list.count; i++)
{

//创建根节点下的子节点
xmlelement xmlperson = xmldoc.createelement("person");

//创建子节点的属性id
xmlattribute xmlattribute = xmldoc.createattribute("id");

//给属性值赋值
xmlattribute.value = (i + 1).tostring();

//添加到子节点中
xmlperson.attributes.append(xmlattribute);

//添加name节点

xmlelement xmlname = xmldoc.createelement("name");

//给name文本赋值
xmlname.innertext = list[i].name;

//添加到person节点下
xmlperson.appendchild(xmlname);

//以下节点类似

xmlelement xmlage = xmldoc.createelement("age");
xmlage.innertext = list[i].age.tostring();
xmlperson.appendchild(xmlage);

xmlelement xmlemail = xmldoc.createelement("email");
xmlemail.innertext = list[i].email;
xmlperson.appendchild(xmlemail);

xmlelement.appendchild(xmlperson);

}

//创建文件保存在xml文件夹中

string filename = server.mappath("/xml/list.xml");

xmldoc.save(filename);