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php 错误:unexpected '$staff'

程序员文章站 2022-05-07 15:24:58
...
这是源码:
 "x","number" => "101","sex" => "male","job" => "manager"),
        array("name" => "y","number" => "102","sex" => "male","job" => "manager"),
        array("name" => "z","number" => "103","sex" => "male","job" => "manager"),
    );
if ($_SERVER["REQUEST_METHOD"] == "GET") {
    search();
}elseif ($_SERVER["REQUEST_METHOD"] == "POST") {
    create();
}

function search() {
    if (!isset($_GET["number"]) || empty($_GET["number"])) {
        echo "error";
        return;
    }
    global $staff
    $number = $_GET["number"];
    $result = "error";
    foreach ($staff as $key => $value) {
        if ($value["number"] == $number) {
            $result = "The person's ID is".$value["number;"]."He's name is".$value["name;"]."And sex is".$value["sex"]."The job".$value["job"];
            break;
        }
    }
    echo $result;
}
function create() {
    if (!isset($_POST["name"]) || empty($_POST["name"]) ||
        !isset($_POST["number"]) || empty($_POST["number"]) ||
        !isset($_POST["sex"]) || empty($_POST["sex"]) ||
        !isset($_POST["job"]) || empty($_POST["job"]) {
        echo "

error

"; return; } echo "The person".$_POST["name"]."save success"; } ?>

然后报错:
Parse error: syntax error, unexpected '$staff' (T_VARIABLE) in D:\wamp\www\test\query.php on line 4

回复内容:

这是源码:

 "x","number" => "101","sex" => "male","job" => "manager"),
        array("name" => "y","number" => "102","sex" => "male","job" => "manager"),
        array("name" => "z","number" => "103","sex" => "male","job" => "manager"),
    );
if ($_SERVER["REQUEST_METHOD"] == "GET") {
    search();
}elseif ($_SERVER["REQUEST_METHOD"] == "POST") {
    create();
}

function search() {
    if (!isset($_GET["number"]) || empty($_GET["number"])) {
        echo "error";
        return;
    }
    global $staff
    $number = $_GET["number"];
    $result = "error";
    foreach ($staff as $key => $value) {
        if ($value["number"] == $number) {
            $result = "The person's ID is".$value["number;"]."He's name is".$value["name;"]."And sex is".$value["sex"]."The job".$value["job"];
            break;
        }
    }
    echo $result;
}
function create() {
    if (!isset($_POST["name"]) || empty($_POST["name"]) ||
        !isset($_POST["number"]) || empty($_POST["number"]) ||
        !isset($_POST["sex"]) || empty($_POST["sex"]) ||
        !isset($_POST["job"]) || empty($_POST["job"]) {
        echo "

error

"; return; } echo "The person".$_POST["name"]."save success"; } ?>

然后报错:
Parse error: syntax error, unexpected '$staff' (T_VARIABLE) in D:\wamp\www\test\query.php on line 4

$staff前,header()这行没有用分号;结束。语法错误。
21和36行也有
新手用个ide比较好。

改为这样:

 "x","number" => "101","sex" => "male","job" => "manager"),
        array("name" => "y","number" => "102","sex" => "male","job" => "manager"),
        array("name" => "z","number" => "103","sex" => "male","job" => "manager"),
    );

22 行 和 36行也有错误

相关标签: php