yii2 - PHP 中的 new static($user) 有何作用，如何理解

如何理解PHP中的 new static() 的用法
在yii2的用户登录处理模型/model/User.php 看到了这一段：

php [
            'id' => '100',
            'username' => 'admin',
            'password' => 'admin',
            'authKey' => 'test100key',
            'accessToken' => '100-token',
        ],
        '101' => [
            'id' => '101',
            'username' => 'demo',
            'password' => 'demo',
            'authKey' => 'test101key',
            'accessToken' => '101-token',
        ],
    ];

    /**
     * @inheritdoc
     */
    public static function findIdentity($id)
    {
        return isset(self::$users[$id]) ? new static(self::$users[$id]) : null;
    }

    /**
     * @inheritdoc
     */
    public static function findIdentityByAccessToken($token, $type = null)
    {
        foreach (self::$users as $user) {
            if ($user['accessToken'] === $token) {
                return new static($user);
            }
        }

        return null;
    }

    /**
     * Finds user by username
     *
     * @param  string      $username
     * @return static|null
     */
    public static function findByUsername($username)
    {
        foreach (self::$users as $user) {
            if (strcasecmp($user['username'], $username) === 0) {
                return new static($user);
            }
        }

        return null;
    }

    /**
     * @inheritdoc
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * @inheritdoc
     */
    public function getAuthKey()
    {
        return $this->authKey;
    }

    /**
     * @inheritdoc
     */
    public function validateAuthKey($authKey)
    {
        return $this->authKey === $authKey;
    }

    /**
     * Validates password
     *
     * @param  string  $password password to validate
     * @return boolean if password provided is valid for current user
     */
    public function validatePassword($password)
    {
        return $this->password === $password;
    }
}

return $user ? new static($user) : null，如果 self::$sers[$id] 里面没有 User 类定义的这些属性，返回就会报错，为什么会这样。如何理解

回复内容：

如何理解PHP中的 new static() 的用法
在yii2的用户登录处理模型/model/User.php 看到了这一段：

php [
            'id' => '100',
            'username' => 'admin',
            'password' => 'admin',
            'authKey' => 'test100key',
            'accessToken' => '100-token',
        ],
        '101' => [
            'id' => '101',
            'username' => 'demo',
            'password' => 'demo',
            'authKey' => 'test101key',
            'accessToken' => '101-token',
        ],
    ];

    /**
     * @inheritdoc
     */
    public static function findIdentity($id)
    {
        return isset(self::$users[$id]) ? new static(self::$users[$id]) : null;
    }

    /**
     * @inheritdoc
     */
    public static function findIdentityByAccessToken($token, $type = null)
    {
        foreach (self::$users as $user) {
            if ($user['accessToken'] === $token) {
                return new static($user);
            }
        }

        return null;
    }

    /**
     * Finds user by username
     *
     * @param  string      $username
     * @return static|null
     */
    public static function findByUsername($username)
    {
        foreach (self::$users as $user) {
            if (strcasecmp($user['username'], $username) === 0) {
                return new static($user);
            }
        }

        return null;
    }

    /**
     * @inheritdoc
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * @inheritdoc
     */
    public function getAuthKey()
    {
        return $this->authKey;
    }

    /**
     * @inheritdoc
     */
    public function validateAuthKey($authKey)
    {
        return $this->authKey === $authKey;
    }

    /**
     * Validates password
     *
     * @param  string  $password password to validate
     * @return boolean if password provided is valid for current user
     */
    public function validatePassword($password)
    {
        return $this->password === $password;
    }
}

return $user ? new static($user) : null，如果 self::$sers[$id] 里面没有 User 类定义的这些属性，返回就会报错，为什么会这样。如何理解

http://*.com/questions/5197300/new-self-vs-new-static

这里有说明

new static : 创建入口对象的新对象。
new self : 创建拥有此方法对象的新对象。
new parent : 创建拥有此方法对象父类的新对象。