jquery ajaxSubmit 异步提交的简单实现_jquery

前台js

$("#nickForm").ajaxSubmit({
type: "post",
url: "http://localhost:8080/test/myspace.do?method=updateNick&param=1",
dataType: "json",
success: function(result){

//返回提示信息
alert(result.nickMsg);
}
});

后台封装：

public ActionForward toUpdateNickName(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response){

PrintWriter pw = response.getWriter();
JSONObject obj = new JSONObject();

obj.put("nickMsg", "昵称修改成功！");

pw.print(obj);
pw.close();

}