XML节点提取问题
现有代码见下:
/* $xmlstring 原内容:
**
-
*/
$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
foreach ($users as $user) {
$html .= 'outputCustomer:'.get_txt($user,'Customer').'
';
$html .= 'outputGeo:'.get_txt($user,'GeocallCLI').'
';
}
echo $html;
function get_txt($parent, $name) {
$nodes = $parent->getElementsByTagName($name);
return $nodes->item(0)->nodeValue;
}
?>
回复内容:
现有的PHP代码输出XML节点时,只能输出第一个同名节点内容"100". 请问怎样才能输出所有节点的内容呢?
现有代码见下:
/* $xmlstring 原内容:
**
-
*/
$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
foreach ($users as $user) {
$html .= 'outputCustomer:'.get_txt($user,'Customer').'
';
$html .= 'outputGeo:'.get_txt($user,'GeocallCLI').'
';
}
echo $html;
function get_txt($parent, $name) {
$nodes = $parent->getElementsByTagName($name);
return $nodes->item(0)->nodeValue;
}
?>
最后一行代码
return $nodes->item(0)->nodeValue;
因为只返回item(0)
所以只看得到一个100
只需检测$nodes的长度,循环输出即可
代码
id*cn 100 101 102 103 105 ';
$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
$html = '';
foreach ($users as $user) {
$html .= get_txt($user, 'Customer') . '
';
$html .= get_txt($user, 'GeocallCLI') . '
';
}
echo $html;
function get_txt($parent, $name)
{
$nodes = $parent->getElementsByTagName($name);
$data = '';
for ($i = 0; $i length; $i++) {
$data .= 'output' . $name . ':' . $nodes->item($i)->nodeValue . '
';
}
return $data;
}
?>
可否代码示例,谢谢!
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